如何加入两个json路径查询在jeter的json路径提取器？

Question

假设我有这个流行的数据样本。

{
    "store": {
        "book": [
            {
                "category": "reference",
                "author": "Nigel Rees",
                "title": "Sayings of the Century",
                "price": 8.95
            },
            {
                "category": "fiction",
                "author": "Evelyn Waugh",
                "color": "red", 
                "title": "Sword of Honour",
                "price": 12.99
            },
            {
                "category": "fiction",
                "author": "Herman Melville",
                "color": "blue", 
                "title": "Moby Dick",
                "isbn": "0-553-21311-3",
                "price": 8.99
            },
            {
                "category": "fiction",
                "author": "J. R. R. Tolkien",
                "title": "The Lord of the Rings",
                "isbn": "0-395-19395-8",
                "price": 22.99
            }
        ],
        "bicycle": {
            "color": "red",
            "price": 19.95
        }
    },
    "expensive": 10
}

我想从这里得到的是一本所有的<代码>书，其中<代码>类别==小说和所有的<代码>自行车，其中<代码>颜色==红色。

也就是说，我想要，

   {
        "category": "fiction",
        "author": "Evelyn Waugh",
        "color": "red", 
        "title": "Sword of Honour",
        "price": 12.99
    },
    {
        "category": "fiction",
        "author": "Herman Melville",
        "color": "blue", 
        "title": "Moby Dick",
        "isbn": "0-553-21311-3",
        "price": 8.99
    },
    {
        "category": "fiction",
        "author": "J. R. R. Tolkien",
        "title": "The Lord of the Rings",
        "isbn": "0-395-19395-8",
        "price": 22.99
    },
    "bicycle": {
         "color": "red",
         "price": 19.95
    }

我知道，我可以用$.store.book[？（=="小说"）]实现有针对性的书籍和$.store.bicycle[？（实现自行车的针对性。

但我怎样才能同时做到这两个呢？




Answer 1

要归还书籍和自行车，您需要：

$..*[?(@.color== 'red' || @.category == 'fiction')] 

对于颜色==红色或类别==小说的书籍，您需要：

$.store.*[?(@.color== 'red' || @.category == 'fiction')] 

Answer 2

我建议使用JSR223后处理器和Groovy语言实现您的场景。从过滤数据中提取元素并构建新JSON的示例代码如下所示：

import groovy.json.JsonBuilder
import groovy.json.JsonSlurper

def json = new JsonSlurper().parseText(prev.getResponseDataAsString())

def fictionBooks = json.store.book.findAll {it.category == "fiction"}
def redBikes = json.store.bicycle.findAll{it.color="red"}

JsonBuilder builder = new JsonBuilder(fictionBooks + redBikes)

prev.setResponseData(builder.toPrettyString())

上面的代码将用过滤的JSON替换父采样器响应数据

参考文献：

• Groovy：解析和生成JSON

Answer 3

您可以使用

$. store.*[？（红色' || @.类别）

将获取您想要的结果