在套接字连接中未获得响应

Question

    if (nsocket.isConnected()) {} 

public class WebService {

public static String devicelisting() {
    Socket nsocket;

    String response = null;

    try {
        nsocket = new Socket("192.168.1.1", 6666);
        if (nsocket.isConnected()) {

            JSONObject json = new JSONObject();
            json.put("cmd", "request_get_file_list");
            json.put("verification", "CVS");
            Log.i("AsyncTask", "doInBackground: Creating socket");
            // nsocket = new Socket();
             OutputStreamWriter out = new OutputStreamWriter(nsocket.getOutputStream(), StandardCharsets.UTF_8);
                out.write(json.toString());
            Log.i("Webservice", "json.toString"+json.toString());

            InputStream in = new BufferedInputStream(nsocket.getInputStream());
            BufferedReader r = new BufferedReader(new InputStreamReader(in));
            StringBuilder stringbuilder = new StringBuilder();
            String line;
            while ((line = r.readLine()) != null) {
                stringbuilder.append(line);
                Log.i("line", "line.line"+line);
            }


            response = stringbuilder.toString();
            Log.i("Response", response);
        }
        else{
            Log.i("Response", "not connected");

        }

    } catch (ProtocolException e) {
        e.printStackTrace();
    } catch (MalformedURLException e) {
        e.printStackTrace();
    } catch (UnknownHostException e) {
        e.printStackTrace();
    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    } catch (JSONException e) {
        e.printStackTrace();
    }
    return response;
}

请帮我找出问题所在。我太过分了，请帮我解决这个问题

Answer 1

对于套接字驱动的事件，很难实现许多功能，而有一些（开源的）库可以实现这样的任务。考虑使用socket.io。

Properties headers = new Properties();
headers.setProperty("Content-Type","application/json"); // your headers
SocketIO socketIO = SocketIO(url, headers);

欲了解更多信息，请参阅SocketIO文档

编辑