函数不被使用时调用[重复]

Question

这是python游戏的基本战利品表。

1. 常见的，如果滴滚动到任何数字，包括13
2. 不寻常，如果下降滚动14通过，并在18
3. 如果跌落在19或20滚动

即使在满足条件的情况下，该程序也会忽略罕见掉落表，而是从罕见掉落表中取出一个项目，例如掉落=20 1000金币

有人能解释一下这里的问题吗？

import random


player_won = True

def common():
    common_drop= ['Dragon Bones','Dragon Hide','Dragon Teath','Steel Scimitar','Iron Arrows','Bronze Kitesheild']
    print(random.choice(common_drop))
    

def uncommon():
    uncommon_drop= ['Rune Platebody','1000 Gold Coins','Dragonstone','Rune longsword','Mithril Javelin','Rune Med Helm']
    print(random.choice(uncommon_drop))
    
    
def rare():
    rare_drop= ['Dragon Head','Gold Trimmed Rune Full Helm','Crystal Halberd','Diamond (uncut)']
    print(random.choice(rare_drop))    

while player_won == True:
    drop = random.randint(1,20)
    print(drop)
    if drop <= 13:
        common() 
    elif drop > 13 <= 18:
        uncommon()
    elif drop == 19 or 20:
        rare()
    break        

Answer 1

您需要在elif中移动drop变量；看来

elif 13 < drop <= 18: