Swift for loop“表达式类型”[[String:String]]”在没有更多上下文的情况下不明确

Question

我试图从字典数组访问以下项目，我有两个问题（两者都是不同的方法）。字典数组初始化如下：

var testingArray = [[String: String]()]

testingArray.append(["name": "Ethiopia", "url": "localhost:8088"])
testingArray.append(["name": "Bugatti", "url": "localhost:8088"])
testingArray.append(["name": "Brazil", "url": "localhost:8088"])
testingArray.append(["name": "Jasmine", "url": "localhost:8088"])
testingArray.append(["name": "Hello", "url": "localhost:8088"])

第一种方法：

for (k,v) in testingArray {
    // code here
}

无法运行，原因是（出现在for循环初始化行上）：

"Expression type '[[String : String]]' is ambiguous without more context

第二种方法：

for indices in testingArray {
    for(k, v) in indices {
        print(indices.keys)
    }
}

返回以下内容：

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Ethiopia"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Ethiopia"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Bugatti"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Bugatti"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Brazil"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Brazil"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Jasmine"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Jasmine"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Hello"], _transform: (Function))

LazyMapCollection<Dictionary<String, String>, String>(_base: ["url": "localhost:8088", "name": "Hello"], _transform: (Function))

下面是我试图实现的伪代码等价物：

for(int i = 0; i < sizeOfArray; i++ {
    print testingArray[i]."name"
    print testingArray[i]."url"
}

这几天我一直在琢磨这个问题，但我对swift及其习惯用法还不太了解，无法单独解决这个问题，任何帮助都将不胜感激（特别是如果我们能够找出如何使#1工作）。

Answer 1

这很有效

for (k,v) in testingArray.enumerated() {
    for (_, element) in k.enumerated(){
       guard let elem = element.value as? [String: Any] else {
            continue
       }
       print elem["name"]
    }
}

Answer 2

我同意错误信息令人困惑/误导。但是testingArray中（k，v）的没有意义，因为testingArray是一个数组，而不是字典。它的元素是字典。

我想你在找这样的东西：

for obj in testingArray {
    print(obj["name"])
    print(obj["url"])
}