如何从Json数据创建TypeScript类？[副本]

Question

我使用Angular调用外部API。Json数据的格式如下：

[
      {
        "AccessGroupsIdList": [],
        "FirstName": "Greg",
        "LastName": "Tipton",
        "LocationIdList": [],
        "PermissionProfile": {
          "Name": "Agent",
          "PermissionProfileId": {
            "ID": "xy678219-bd7c-103d-b56b-1f1234a85990"
          },
          "Type": 3
        },
        "ManagerName": "Gilchrist, George",
        "Status": true,
        "UserGroupID": {
          "ID": "00000000-0000-0000-0000-000000000000"
        },
        "UserGroupName": "ROOT",
        "UserId": {
          "ID": "4445cc66-819a-4da0-8fbf-d0bb8ce65941"
        }
      }
    ]

既然json数据是嵌套的，我如何在typescript中创建一个类来读取它？

export class Employees
{
    AccessGroupsIdList: string[];
    FirstName: string;
    LastName: string;
    LocationIdList : number[];
    PermissionProfile ??
    ManagerName: string;
    Status: boolean;
    UserGroupID ??
    UserGroupName : string;
    UserId ??
}

请指导如果PermissionProfile，PermissionProfile将是独立的嵌套类？

我该如何申报？

Answer 1

尝试如下声明TypeScript类结构：

export class Employees
{
    AccessGroupsIdList: string[];
    FirstName: string;
    LastName: string;
    LocationIdList : number[];
    PermissionProfile: PermissionProfile;
    ManagerName: string;
    Status: boolean;
    UserGroupId: UserGroupID;
    UserGroupName : string;
    UserId: UserID;
}

export class PermissionProfile 
{
    name: string;
    permissionProfileId: PermissionProfileID;
    type: string;
}

export class PermissionProfileID
{
    id: string;
}
 
export class UserGroupID
{
    id: string;
}

export class UserID
{
    id: string;
}

我建议使用Id（例如，UserGroupId）统一命名属性名称。name和type类属性名称在TypeScript中有效（与C#语法不同）。

Answer 2

为了扩展Andrew Halil的回答，我将在您的定义中使用接口而不是类，因为似乎没有涉及任何类方法；您只是描述从服务器返回的JSON对象的形状

export interface Employee
{
    AccessGroupsIdList: string[];
    FirstName: string;
    LastName: string;
    LocationIdList : number[];
    PermissionProfile: PermissionProfile;
    ManagerName: string;
    Status: boolean;
    UserGroupId: ID;
    UserGroupName : string;
    UserId: ID;
}

export interface PermissionProfile 
{
    name: string;
    permissionProfileId: ID;
    type: string;
}

export interface ID
{
    id: string;
}
 

现在对于一个实现，我不太使用Angular，但是您可以这样做来输入条目

async function listEmployees(): Promise<Employee[]> {
// Make a fetch call to the API endpoint
   const data = await fetch('https://some-api-endpoint.web/employees')
      // if the response comes back ok, return the JSON-ified response.
      .then(res => {
          if(res.ok) return res.json()
          return [];
      });
    // Instruct typescript that "data" is to be treated as an array of Employee elements.
    return data as Employee[]
}