如何在javascript中找到arr1中的元素是否也在arr2中？[副本]

Question

例如，我有两个阵列：

arr1 = ["a","e","i","o","u"];
arr2 = ["h", "e", "l", "l", "o"];

我想知道arr2中的任何元素是否包含arr1中已有的任何元素。

Answer 1

试试这个。

arr1 = ["a","e","i","o","u"]; 
arr2 = ["h", "e", "l", "l", "o"];

let res = arr1.some(el1 => {
    return arr2.some(el2 => el1 === el2);
});

console.log(res) // true

Answer 2

使用下面的筛选函数查找数组

let array1 = ["a","e","i","o","u"]; 
let array2 = ["h", "e", "l", "l", "o"];

const filteredArray = array1.filter(value => array2.includes(value));

filteredArray.length将为您提供答案

Answer 3

使用Array.some检查arr2中的一项是否包含在arr1中：

arr1 = ["a", "e", "i", "o", "u"];
arr2 = ["h", "e", "l", "l", "o"];

const res = arr2.some(e => arr1.includes(e))
console.log(res)