联合字段的Avro无效默认值

Question

我正在尝试序列化一个avro模式，然后将其写入hortonworks模式注册表，但在写入操作期间收到以下错误消息。

Caused by: java.lang.RuntimeException: An exception was thrown while processing request with message: [Invalid default for field viewingMode: null not a [{"type":"record","name":"aName","namespace":"domain.assembled","fields":[{"name":"aKey","type":"string"}]},{"type":"record","name":"anotherName","namespace":"domain.assembled","fields":[{"name":"anotherKey","type":"string"},{"name":"yetAnotherKey","type":"string"}]}]]
        at com.hortonworks.registries.schemaregistry.client.SchemaRegistryClient.handleSchemaIdVersionResponse(SchemaRegistryClient.java:678)
        at com.hortonworks.registries.schemaregistry.client.SchemaRegistryClient.doAddSchemaVersion(SchemaRegistryClient.java:664)
        at com.hortonworks.registries.schemaregistry.client.SchemaRegistryClient.lambda$addSchemaVersion$1(SchemaRegistryClient.java:591)

这是avro模式

{
    "type": "record",
    "name": "aSchema",
    "namespace": "domain.assembled",
    "fields": [
        {
            "name": "viewingMode",
            "type": [
                {
                    "name": "aName",
                    "type": "record",
                    "fields": [
                        {"name": "aKey","type": "string"}
                    ]
                },
                {
                    "name": "anotherName",
                    "type": "record",
                    "fields": [
                        {"name": "anotherKey","type": "string"},
                        {"name": "yetAnotherKey","type": "string"}
                    ]
                }
            ]
        }
    ]
}

无论谁，如果我添加“null”作为联合的第一种类型，都会成功。avro联合类型需要“null”吗？在我的情况下，这将是不正确的数据表示，所以我不热衷于这样做。如果有什么不同，我使用avro 1.9.1。

此外，如果标签不正确，但找不到hortonworks-模式-注册表标签并且没有足够的代表来创建新标签，请道歉。

Answer 1

结果是hortonwork的模式注册表出现了问题。这实际上已经在这里被修复了，我已经要求在这里发布一个新版本。希望这很快就会发生。