打开和关闭spring security SAML的方法

Question

除了其他身份验证机制外，我还在应用程序中实现了spring security saml的一个相当标准的实现。开箱即用的SAML不会配置，但可以通过表单配置，因此默认情况下应该禁用SAML。我希望能够轻松地切换SAML开/关，但不确定这样做的最佳方式是什么。

<http auto-config="false" use-expressions="true"
      access-decision-manager-ref="webAccessDecisionManager"
      disable-url-rewriting="false"
      create-session="never"
      authentication-manager-ref="authenticationManager">

    <custom-filter before="FIRST" ref="metadataGeneratorFilter"/>
    <custom-filter after="BASIC_AUTH_FILTER" ref="samlFilter"/>
</http>

<beans:bean id="metadataGeneratorFilter" class="org.springframework.security.saml.metadata.MetadataGeneratorFilter">
    <beans:constructor-arg>
        <beans:bean class="org.springframework.security.saml.metadata.MetadataGenerator">
            <beans:property name="entityId" value="${saml.entityId}"/>
            <beans:property name="signMetadata" value="${saml.signMetadata}"/>
        </beans:bean>
    </beans:constructor-arg>
</beans:bean>

<beans:bean id="samlFilter" class="org.springframework.security.web.FilterChainProxy">
    <filter-chain-map request-matcher="ant">
        <filter-chain pattern="/saml/login/**" filters="samlEntryPoint"/>
        <filter-chain pattern="/saml/logout/**" filters="samlLogoutFilter"/>
        <filter-chain pattern="/saml/metadata/**" filters="metadataDisplayFilter"/>
        <filter-chain pattern="/saml/SSO/**" filters="samlWebSSOProcessingFilter"/>
        <filter-chain pattern="/saml/SSOHoK/**" filters="samlWebSSOHoKProcessingFilter"/>
        <filter-chain pattern="/saml/SingleLogout/**" filters="samlLogoutProcessingFilter"/>
        <filter-chain pattern="/saml/discovery/**" filters="samlIDPDiscovery"/>
    </filter-chain-map>
</beans:bean>

public class MyMetadataGeneratorFilter extends MetadataGeneratorFilter {

    private boolean isActive = false;

    public MyMetadataGeneratorFilter(MetadataGenerator generator) {
        super(generator);
    }

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)
            throws IOException, ServletException {
        if (isActive) {
            processMetadataInitialization((HttpServletRequest) request);
        }
        chain.doFilter(request, response);
    }

    public void setActive(boolean active) {
        isActive = active;
    }
}

初始化后,我获得filterchainmap值：

private Map<RequestMatcher, List<Filter>> map;

@Override
public void init() throws ServiceException, MetadataProviderException {

    SamlConfig samlConfig = getConfig();
    map = samlFilter.getFilterChainMap();

    applySamlConfig(samlConfig);

}

在下面的方法中，我将过滤器链映射设置为spring xml中提供的原始映射（如果启用）或空映射（如果禁用）。

public void applySamlConfig(SamlConfig samlConfig) throws ServiceException, MetadataProviderException {


    if (!samlConfig.isEnabled()) {
        Map<RequestMatcher, List<Filter>> emptyMap = samlFilter.getFilterChainMap();
        emptyMap.clear();
        samlFilter.setFilterChainMap(emptyMap);
        return;
    }

    samlFilter.setFilterChainMap(map);

Answer 1

我在entry-point-ref定义中添加了一个自定义筛选器。如果未启用该功能，则此筛选器将跳过以下所有筛选器。

<security:http entry-point-ref="samlEntryPoint">
  <security:intercept-url pattern="/**" access="IS_AUTHENTICATED_FULLY" />
  <!-- This filter checks if the SSO-Feature is enabled - otherwise all following security filters will be skipped -->
  <security:custom-filter before="BASIC_AUTH_FILTER" ref="ssoEnabledFilter"/>
  <security:custom-filter before="FIRST" ref="metadataGeneratorFilter" />
  <security:custom-filter after="BASIC_AUTH_FILTER" ref="samlFilter" />

SsoEnabledFilter：

    public class SsoEnabledFilter extends GenericFilterBean {

    @Override
    public void doFilter(final ServletRequest request, final ServletResponse response, final FilterChain filterChain) throws IOException, ServletException {
        boolean ssoEnabled = isSsoEnabled();

        if (ssoEnabled) {
            filterChain.doFilter(request, response);
        } else {
            request.getRequestDispatcher(((HttpServletRequest) request).getServletPath()).forward(request, response);
        }
      }
   }