RestSharp GetAsync忽略响应错误状态代码

Question

我是不是漏掉了什么？我应该如何使用这些异步方法来处理这样的错误响应呢？

Answer 1

那行为也让我很反感。

查看GitHub中RestClientExtensions的源代码，getAsync方法实现为：

public static async Task<T> GetAsync<T>(this IRestClient client, IRestRequest request, CancellationToken cancellationToken = default)
{
    var response = await client.ExecuteGetAsync<T>(request, cancellationToken);
    ThrowIfError(response);
    return response.Data;
}

您希望throwiferror会查看HTTP状态代码，但查看RestSharp文档中的错误处理，它会显示：

static void ThrowIfError(IRestResponse response)
{
    var exception = response.ResponseStatus switch
    {
        ResponseStatus.Aborted   => new WebException("Request aborted", response.ErrorException),
        ResponseStatus.Error     => response.ErrorException,
        ResponseStatus.TimedOut  => new TimeoutException("Request timed out", response.ErrorException),
        ResponseStatus.None      => null,
        ResponseStatus.Completed => null,
        _                        => throw response.ErrorException ?? new ArgumentOutOfRangeException()
    };

    if (exception != null)
        throw exception;
}

关于你的问题：

我应该如何使用这些异步方法来处理这样的错误响应呢？

你不能：（。

private Task<T> GetAsync<T>(RestRequest request)
{
    return Task.Run(() =>
    {
        var response = client.Get<T>(request);
        if (response.IsSuccessful)
            return response.Data;

        //handle the errors as you wish. In my case, the api I work with always
        //returns a bad request with a message property when it occurs...
        var errorData = JsonConvert.DeserializeObject<ApiMessage>(response.Content);
        throw new Exception(errorData.Message);
    });
}

public class ApiMessage
{
    public string Message { get; set; }
}

public Task<MyModel> SomeRequest()
{
    var request = new RestRequest()
    {
        Resource = "some-resource",
    };

    return GetAsync<MyModel>(request);
}