LWJGL按住一个键

Question

所以最基本的，我想做的是使用LWJGL让我的球员在比赛中移动。玩家当前正在移动，但当你按住按钮时，他没有继续移动。

        if(Keyboard.getEventKey() == Keyboard.KEY_RIGHT) {
            if(Keyboard.getEventKeyState()){
                System.out.println("KEY DOWN!");
                player.playerMovingRight();
            }
            else{
                System.out.println("KEY RELEASED!");
            }
        }
    }

更新的代码：

public void update(){
    while(Keyboard.next()){

        //If key escape is down we shut the application down
        if(Keyboard.isKeyDown(Keyboard.KEY_ESCAPE)){
            System.exit(0);
        }

        //If key up was pressed move up
        else if(Keyboard.getEventKey() == Keyboard.KEY_UP) {
            if(Keyboard.getEventKeyState()){
                System.out.println("KEY DOWN!");
                moveUp = true;
            }
            else{
                System.out.println("KEY RELEASED!");
                moveUp = false;
            }
        }
        //If key down was pressed move down
        else if(Keyboard.getEventKey() == Keyboard.KEY_DOWN) {
            if(Keyboard.getEventKeyState()){
                System.out.println("KEY DOWN!");
                moveDown = true;
            }
            else{
                System.out.println("KEY RELEASED!");
                moveDown = false;
            }
        }

        if(moveUp == true){
            player.playerMovingUp();
        }
        if(moveDown == true){
            player.playerMovingDown();
        }
    }

我的代码仍然有同样的问题，我开始认为是Keyboard.next（）阻止了我按住按钮，而播放器仍然在移动。

Answer 1

您需要的是一个布尔标志，它在按下按钮时触发，在释放按钮时不触发。然后将该标志添加到移动代码之前的if语句中。例如：

if(Keyboard.getEventKey() == Keyboard.KEY_RIGHT) {
        if(Keyboard.getEventKeyState()){
            System.out.println("KEY DOWN!");
            flag = true;       
        }
        else{
            System.out.println("KEY RELEASED!");
            flag = false;
        }
    }
}

//player movement code

if(flag) {
    player.playerMovingRight();
}

使用多个键的方法是使用布尔触发器数组并重复检查每个键。