Java-输入不匹配异常不工作

Question

（更新的代码）无论出于什么原因，InputMismatchException的catch块无法正常工作。当代码抛出此错误时，catch块不会捕获它。有人知道为什么会这样吗？

import java.util.*;
public class ArrayException {
    
    public String getPriceDetails() {
        Scanner scnr = new Scanner(System.in);
        
        System.out.println("Enter the number of elements in the array");
        int num = scnr.nextInt();
        int array[] = new int[num];
        
        System.out.println("Enter the price details");
        
        for (int i = 0; i < num; ++i) {
            array[i] = scnr.nextInt();
        }
        
        System.out.println("Enter the index of the array element you want to access");
        
        try {
            int index = scnr.nextInt();
            return "The array element is " + array[index];
        } catch (InputMismatchException e) {
            return "Input was not in the correct format";
        } catch (ArrayIndexOutOfBoundsException e) {
            return "Array index is out of range";
        }
        
    }
    
    public static void main(String[] args) {
        Scanner scnr = new Scanner(System.in);
        ArrayException mn = new ArrayException();
        
        String test = mn.getPriceDetails();
        System.out.print(test);
    }
}

Answer 1

添加以下catch块以找出正在抛出的十六进制异常。也许会抛出另一个异常。

catch (Exception e){
    // Prints what exception has been thrown
    System.out.println(e);
}

我希望这对你有帮助。