即使只在一个listView项中按下按钮，也会按下多个listView项按钮

Question

 @Override
public View getView(int position, View convertView, ViewGroup parent) 
{

    View listItemView = convertView;
    if (listItemView == null) {
        listItemView = LayoutInflater.from(getContext()).inflate(
                R.layout.list_item, parent, false);
        likeButton= (Button) 
 listItemView.findViewById(R.id.like_button);
        //likeButton.setClickable(currentProduct.getmLikeButton());
        dislikeButton = (Button) 
 listItemView.findViewById(R.id.dislike_button);

        favoritesButton = (Button) 
  listItemView.findViewById(R.id.favorite_button);
    }

    TextView productNameView = (TextView) 
 listItemView.findViewById(R.id.product_name);
    ImageView productImageView = (ImageView) 
  listItemView.findViewById(R.id.product_image);

    currentProduct = getItem(position);
    likeButton.setTag(position);
    dislikeButton.setTag(position);
    favoritesButton.setTag(position);

    likeButton.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {

            int position=(Integer)v.getTag();
            currentProduct = getItem(position);
            productId = currentProduct.getProductId();

            likeButton = (Button) v.findViewById(R.id.like_button);

            Uri baseUri = Uri.parse(UNBXD_UACTION);
                Uri.Builder uriBuilder = baseUri.buildUpon();
                uriBuilder.appendQueryParameter("uaction", "like");
                uriBuilder.appendQueryParameter("user", "8222");
                uriBuilder.appendQueryParameter(PRODUCT_ID,productId);
                uriBuilder.appendQueryParameter(MATERIALL, "true");
                //uriBuilder.appendQueryParameter(USER_ID, "5");
                uriBuilder.appendQueryParameter(UNDO, "false");
                Intent intent = new 
                Intent(Intent.ACTION_WEB_SEARCH, uriBuilder.build());
                intent.getData();
                likeButton.setBackgroundResource(R.drawable.liked);
Log.v("liked url is ", uriBuilder.toString() + " " + 
String.valueOf(position));
        }
    });

我无法弄清楚每三个条目的like按钮是如何以及为什么被按下的，从我实际按下的like按钮开始，但（幸运的是）只有一个，而且也调用了正确的API。

请帮忙。

Answer 1

这是因为您的视图是在listview中回收的。当convertview！=null时，这意味着您得到了一个回收的视图，并且需要再次绑定该视图。

要解决此问题，您可能需要在产品类、适配器或其他地方添加一个新属性，并简化单击监听器中的操作：

likeButton.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {
        int position = (Integer)v.getTag();
        Product currentProduct = getItem(position);
        currentProduct.setLiked(true); // or false
        notifyDataSetChanged(); // notify so ListView can update
    }
// continue...

然后在getview方法中：

@Override
public View getView(int position, View convertView, ViewGroup parent) 
{
    // ...
    likeButton = (Button) v.findViewById(R.id.like_button);
    likeButton.setBackgroundResource(currentProduct.isLiked() ? R.drawable.liked : R.drawable.something);
    // continue...