VSCode+Xdebug+PHP配置

Question

我试图用VScode设置Xdebug，但是每当我设置断点时，它就会忽略它。

{
  "name": "Listen for XDebug",
  "type": "php",
  "request": "launch",
  "port": 9000
},
{
  "name": "Launch currently open script",
  "type": "php",
  "request": "launch",
  "program": "${file}",
  "cwd": "${fileDirname}",
  "port": 9000
}

zend_extension = D:\wamp\bin\php\php7.1.16\ext\php_xdebug-2.6.1-7.1-vc14.dll

[XDebug]
xdebug.remote_enable = 1
xdebug.remote_autostart = 1
xdebug.remote_host=localhost
xdebug.remote_port=9000
xdebug.remote_log=D:\wamp\logs\xdebug.log

PHP-V

$ php -v
PHP 7.1.16 (cli) (built: Mar 28 2018 21:27:36) ( ZTS MSVC14 (Visual C++ 2015) x8
6 )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies
with Xdebug v2.6.1, Copyright (c) 2002-2018, by Derick Rethans

感谢您的阅读！

Answer 1

我相信您的php.ini可能需要以下内容：

xdebug.remote_connect_back=1

有关WPLib Box的PHP容器，请参见XDEBUG.ini，它肯定可以使用XDEBUG和VS代码。