在使用jolt转换json键值对时保留一些键值对

Question

{ "first_name": {
    "label": "First name",
    "type": "text",
    "value": "John"
  },
  "last_name": {
    "label": "Last name",
    "type": "text",
    "value": "Doe"
  },
  "email": {
    "label": "Email",
    "type": "text",
    "value": "[e-mail]"
  }
  "id": 123,
  "marital_status": "Single",
  "author_id": null,
  "company": null,
  "address": {
    "city": {
      "label": "city",
      "dom_type": "dropdown",
      "value": "test"
    },
    "state": {
      "label": "state",
      "dom_type": "dropdown",
      "value": "state"
    },
    "country": {
      "label": "country",
      "dom_type": "dropdown",
      "value": "country"
    }
  }
}

{
 "first_name" : "John", "last_name" : "Doe", "email" : "[e-mail]", 
 "id": 123, "marital_status": "Single", "author_id": null, "company": null,
  "address" : { "city" : "test", "state" : "test", "country" : "test" }
}

[
  {
    "operation": "shift",
    "spec": {
      "address": {
        "*": {
          "@value": "address.&1"
        }
      },
      "*": {
        "@value": "&1"
      }
    }
  }
]

{
     "first_name" : "John", "last_name" : "Doe", "email" : "[e-mail]", "address" : { "city" : "test", "state" : "test", "country" : "test" }
 }

因为匹配器“*”丢弃简单键值对。我知道我错过了什么。有人帮忙吗？

Answer 1

因为匹配器“*”丢弃简单键值对。->它不是丢弃它们，而是匹配它们，但没有找到“value”的子属性。

您的输入数据基本上有3种不同的格式

1. 地址下面的东西
2. 单数值的东西，如“id”
3. 具有嵌套数据的东西

[
  {
    "operation": "shift",
    "spec": {
      "address": {
        "*": {
          "@value": "address.&1"
        }
      },
      "id|marital_status|author_id|company": "&",
      "*": {
        "@value": "&1"
      }
    }
  }
]