基于索引值的排序列表

Question

LinkedHashSet<List<String>> sorted = new LinkedHashSet<List<String>>();

List<String> data1 = Database.getData(uuid);
double price = Double.valueOf(data1.get(2))

data1.add("testval");
data1.add("testval");
data1.add("100.00");

sorted.add(data1);

List<String> data2 = Database.getData(uuid);
double price = Double.valueOf(data2.get(2))

data2.add("anotherval");
data2.add("anotherval");
data2.add("50.00");

sorted.add(data2);

按降序排序的LinkedHashSet的输出。

testval testval 100.00
anotherval anotherval 50.00

对不起，如果这是混淆，我不知道如何去排序像这样。

Answer 1

创建一个新类来表示您的复杂对象。如果可以在对象中存储多个值，则不需要在列表中存储多个值。

public class ComplexObject {
    private String description1;
    private String description2;
    private Double value;

    public ComplexObject(String description1, String description2, Double value) {
        this.description1 = description1;
        this.description2 = description2;
        this.value = value;
    }

    public void setDescription1(String description1) {
        this.description1 = description1;
    }

    public String getDescription1() {
        return description1;
    }

    public void setDescription2(String description2) {
        this.description2 = description2;
    }

    public String getDescription2() {
        return description2;
    }

    public void setValue(Double value) {
        this.value = value;
    }

    public Double getValue() {
        return value;
    }
}

然后将元素添加到列表中，并使用新的自定义比较器对其进行排序：

public static void main(String[] args) {

    List<ComplexObject> complexObjectList = new ArrayList<ComplexObject>();

    //add elements to the list
    complexObjectList.add(new ComplexObject("testval","testval",100.00d));
    complexObjectList.add(new ComplexObject("anotherval","anotherval",50.00d));

    //sort the list in descending order based on the value attribute of complexObject
    Collections.sort(complexObjectList, new Comparator<ComplexObject>() {
            public int compare(ComplexObject obj1, ComplexObject obj2) {
                return obj2.getValue().compareTo(obj1.getValue()); //compares 2 Double values, -1 if less , 0 if equal, 1 if greater
            }
        });

    //print objects from sorted list
    for(ComplexObject co : complexObjectList){
        System.out.println(co.getDescription1()+" "+co.getDescription2()+" "+co.getValue());
    }
}

产出：

testval testval 100.0
anotherval anotherval 50.0