JavaFX 等待用户输入

Question

我正在编写一个棋盘游戏，我需要检查玩家正在移动的敌人并提示进行攻击。但是，由于游戏是如何制作的，移动方法是在JavaFX应用程序线程上调用的，我希望能够提示用户是否要与敌人战斗。

我的对话框工作正常，使用等待和通知，在主线程上不工作，会导致程序崩溃，有人知道如何暂停这个线程的执行，直到用户单击其中一个按钮。

我为描述道歉，太晚了。

检查敌人的方法该方法检查敌人，如果用户选择是，则返回敌人。它运行在JavaFX线程上。

private Ship pathBattle(Vector gridPosition){
  //Check if there are ships on the path to the destination
  for(Button cell : activeButtons){
     //Check the button position is not that of the current button, dont go past the current button
     Vector pixPosition = new Vector(cell.getLayoutX(), cell.getLayoutY());
     //Convert to a grid referance
     Vector gridPos = Vector.pixToGrid(pixPosition);
     if(!gridPos.equals(gridPosition)){
        //This button is not the destination

        //Check for any ships on that cell
        Ship collided = Ship.isOccupiedButton(cell);//Returns the ship if there is one on the cell
        if(collided != null){
           //There is a ship, prompt to battle
           boolean battle = UtilPopups.showConfirmationDialog("Do you want to battle " + collided.getName(), "YAR!", "NAY!");

           Game.printError("Ship collision");

           if(battle){
              return collided; //Return the ship to battle
           }
        }
     }

     //On to the next button
  }

  return null;
}

显示Popup的代码这确实适用于porgram的其他区域，没有问题

public static boolean showConfirmationDialog(String lblPrompt, String btnYes, String btnNo){
  //Check if the confirmation controller is not null
  if(confirmationDialog != null){
     confirmationDialog.lbl_prompt.setText(lblPrompt);
     confirmationDialog.btn_no.setText(btnNo);
     confirmationDialog.btn_yes.setText(btnYes);

     //Show the base
     show(confirmationDialog.base_pane);

     //Pause this thread until user input is given from GUI thread
     synchronized (confirmationDialog) {
        try{
           confirmationDialog.wait();
        } catch (Exception e) {
           e.printStackTrace();
        }
     }

     //Program resumed, user input given and stored in response
     if(confirmationDialog.response.equals("yes")){
        confirmationDialog.response = null; //Set back to null
        return true;
     } else {
        confirmationDialog.response = null; //Set back to null
        return false;
     }
  }

  //Class not initialized
  Game.printError("UtilPopups->showConfirmationDialog: Dialog NULL!");
  return false;
}

Answer 1

碰撞方法实际上什么都不做，它不要求输入，所以它不能工作。

我想，抱歉英语不好

Answer 2

用于在显示对话框期间阻止任何呼叫者线程，例如:

static private void showAndBlock(Dialog dialog) {
    if (Platform.isFxApplicationThread()) {
        dialog.showAndWait();
    } else {
        CountDownLatch lock = new CountDownLatch(1);
        Platform.runLater(() -> {
            dialog.showAndWait();
            lock.countDown();
        });
        try {
            lock.await();
        } catch (InterruptedException e) {
            // Just in case you call yourTherad.interrupt(),
            // the thread will be joined forcibly through here.
        }
    }
}

但我不确定它是否适用于您的Thread设计。