Spock spy/mock未注册调用

Question

    public void populateEdgeInfo(Map<Actor, SchedulableNode> knownNodes) {
        populateDestinationInfo(knownNodes);
        populateSourceInfo(knownNodes);
    }

我的测试代码：

def "Populating edge info means both source and destination information will be populated" () {
    given:
    actor.getDstChannels() >> []
    actor.getSrcChannels() >> []
    SchedulableNode schedulable = Spy(SchedulableNode, constructorArgs: [actor])

    when:
    schedulable.populateEdgeInfo([:])

    then:
    1 * schedulable.populateDestinationInfo(_)
    1 * schedulable.populateSourceInfo(_)
}

唯一注册的是对PopulateEdgeInfo的调用。有什么明显的我做错了吗？也试图用模拟代替间谍，但没有用。

Answer 1

我试图从您的稀疏信息中创建一个MCVE，但在您的测试中没有发现任何问题：

package de.scrum_master.stackoverflow.q60926015;

import java.util.List;

public class Actor {
  public List getDstChannels() {
    return null;
  }

  public List getSrcChannels() {
    return null;
  }
}

package de.scrum_master.stackoverflow.q60926015;

import java.util.Map;

public class SchedulableNode {
  private Actor actor;

  public SchedulableNode(Actor actor) {
    this.actor = actor;
  }

  public void populateEdgeInfo(Map<Actor, SchedulableNode> knownNodes) {
    populateDestinationInfo(knownNodes);
    populateSourceInfo(knownNodes);
  }

  public void populateDestinationInfo(Map<Actor, SchedulableNode> knownNodes) {}

  public void populateSourceInfo(Map<Actor, SchedulableNode> knownNodes) {}
}

package de.scrum_master.stackoverflow.q60926015

import spock.lang.Specification

class SchedulableNodeTest extends Specification {
  def actor = Mock(Actor)

  def "Populating edge info means both source and destination information will be populated"() {
    given:
    actor.getDstChannels() >> []
    actor.getSrcChannels() >> []
    SchedulableNode schedulable = Spy(SchedulableNode, constructorArgs: [actor])

    when:
    schedulable.populateEdgeInfo([:])

    then:
    1 * schedulable.populateDestinationInfo(_)
    1 * schedulable.populateSourceInfo(_)
  }
}

这意味着您的代码必须与我的不同。我的猜测是，populate*方法在类中都是private，这使得无法模拟它们，因为模拟使用动态代理，而后者在技术上是子类。子类看不到私有的超类方法，因此动态代理不能截获（对它们的调用）。

可能的解决办法：