java.io.FileNotFoundException：类路径资源，即使文件存在于src/main/resources中

Question

我的XML文件位于src/main/resources目录下。我的spring代码看起来像

import java.io.IOException;
import java.util.concurrent.atomic.AtomicLong;

import com.google.common.base.Charsets;
import com.google.common.io.Files;
import org.springframework.core.io.ClassPathResource;
import org.springframework.integration.xml.transformer.XsltPayloadTransformer;
import org.springframework.messaging.Message;
import org.springframework.messaging.support.MessageBuilder;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.ResponseBody;

@Controller
public class BdeApplicationController {

    @GetMapping("/ping")
    @ResponseBody
    public String ping(@RequestParam(name="name", required=false, defaultValue="Stranger") String name) {
        return myFlow();
    }

    private String myFlow() {
        XsltPayloadTransformer transformer = getXsltTransformer();
        return transformer.transform(buildMessage(getXMLFileString())).toString();
    }

    private String getXMLFileString() {
        try {
            return Files.toString(new ClassPathResource("XML1.xml").getFile(), Charsets.UTF_8);
        } catch (IOException e) {
            e.printStackTrace();
        }
        return "";
    }

    private XsltPayloadTransformer getXsltTransformer() {
        return new XsltPayloadTransformer(new ClassPathResource("XSLT1.xsl"));
    }

    protected Message<?> buildMessage(Object payload) {
        return MessageBuilder.withPayload(payload).build();
    }
}

运行此代码时，我得到以下异常：-

java.io.FileNotFoundException：类路径资源[xml1.xml]无法解析为绝对文件路径，因为它不驻留在文件系统中：jar:file:/users/user/documents/project/target/bde-0.0.1-snapshot.jar！/boot-inf/classes！/xml1.xml

你能建议我怎么修吗？

Answer 1

当您使用resource.getFile（）时，您需要在文件系统中查找该文件，这就是当您将其作为JAR运行时无法工作的原因。

尝试输入流

String data = "";
ClassPathResource resource = new ClassPathResource("/XML1.xml");
try {
    byte[] dataArr = FileCopyUtils.copyToByteArray(resource.getInputStream());
    data = new String(dataArr, StandardCharsets.UTF_8);
} catch (IOException e) {
    // do whatever
}