无法在Python中接收所有MQTT消息

Question

client = mqtt.Client('DataReaderPub')
client.connect('127.0.0.1', 1883, 60)
print("MQTT parameters set.")

# Read from all files
count = 0
for i in range(1,51):
    payload = "Hello world" + str(count)
    client.publish(testtopic, payload, int(publisherqos))
    client.loop()
    count = count+1
    print(count, ' msg sent: ', payload)
    sleep(0.1)

subclient = mqtt.Client("DynamicDetectorSub")
subclient.on_message = on_message
subclient.connect('127.0.0.1')

subclient.subscribe(testtopic, int(subscriberqos))

subclient.loop_forever()

mosquitto.conf将最大飞行消息设置为0，持久性为true。

发布服务器QOS=2

用户QOS=2

保持活力=60

还有其他参数我应该看吗？

Answer 1

您还需要调用publisher中的network loop函数，这样客户机实际上有一些时间来执行IO（以及QOS2的双重握手）。

在客户端中调用client.publish()之后添加client.loop():

import paho.mqtt.client as mqtt
import time

client = mqtt.Client('DataReaderPub')
client.connect('127.0.0.1', 1883, 60)
print("MQTT parameters set.")

# Read from all files
count = 0
for i in range(1,51):
    payload = "Hello world" + str(count)
    client.publish("test", payload, 2)
    client.loop()
    count = count+1
    print(count, ' msg sent: ', payload)
    time.sleep(0.1)

订户代码：

import paho.mqtt.client as mqtt

def on_message(client, userdata, msg):
  print(msg.topic + " " + str(msg.payload))

subclient = mqtt.Client("DynamicDetectorSub")
subclient.on_message = on_message
subclient.connect('127.0.0.1')

subclient.subscribe("test", 2)

subclient.loop_forever()