Python Instagram API-如何根据命中率限制循环访问令牌？

Question

我有一个关于Instagram API和速率限制的问题--以及如何循环访问令牌来解决这个问题。

user_followers, next_ = api.user_followed_by(userid) #request data from API
    while next_:
    more_user_followers, next_ = api.user_followed_by(with_next_url=next_) #extract the list of followers
    user_followers.extend(more_user_followers) #append each page of followers into this list with each iteration

counter=0 #set seed counter

user_followers, next_ = api.user_followed_by(userid) #request data from API
    while next_:
        try:
            more_user_followers, next_ = api.user_followed_by(with_next_url=next_) #extract the list of followers and capture any error codes
        except InstagramAPIError:
            counter=counter+1 #upon rate-limit error, increment counter by 1 to call each access token
            if counter==1:
                access_token="accesstoken1"
            if counter==2:
                access_token="accesstoken2"
            # etc...
                counter=0 #for the final access_token in the list, reset counter to 0 to re-start at the top of the list and cycle until a hit is found
            api=InstagramAPI(access_token=access_token,client_secret=client_secret) #I think this should push the new access_token to the Instagram API constructor, but perhaps this is where the error lies...
            continue #I think this will break the current cycle and restart under the `while next_:` statement, thus attempting to pull the data using the new access token
        user_followers.extend(more_user_followers) #append each page of followers into this list with each iteration

使用try:语句成功捕获了速率限制错误，并且循环将正确地循环访问令牌--但是由于某些原因，这些令牌不会被识别或“推”回Instagram API接口，数据也不会被提取。循环只是不停地在代码中循环。

我知道这是可能的，因为我已经通过手动请求endpoint和在遇到速率限制错误时切换访问令牌（使用另一个软件包）实现了这一点，但我希望使用PythonInstagram API来实现这一点。

我最初的想法是，continue中断不会在适当的上游点重置循环，或者在对user_followers,next_=api.user_followed_by(userid)endpoint的给定调用中不能“切换”访问令牌。

Answer 1

最简单的解决方案-随机获取所有令牌。从统计上看，在多次运行后，负载将几乎相等。

如果他们中的一个突然筋疲力尽--下一个。

    import random
    tokens = ['aaaaa', 'bbbbb', 'cccc', ...]
    token = random.choice(tokens)