在Findbugs中使用“excluses”配置，在Gradle中使用Checkstyle插件

Question

我有以下Gradle构建文件:https://github.com/markuswustenberg/jsense/blob/a796055f984ec309db3cc0f3e8340cbccac36e4e/jsense-protobuf/build.Gradle，其中包括：

checkstyle {
  // TODO The excludes are not working, ignore failures for now
  //excludes '**/org/jsense/serialize/protobuf/gen/**'
  ignoreFailures = true
  showViolations = false
}

findbugs {
  // TODO The excludes are not working, ignore failures for now
  //excludes '**/org/jsense/serialize/protobuf/gen/**'
  ignoreFailures = true
}

tasks.withType(Checkstyle) {
  exclude '**/org/jsense/serialize/protobuf/gen/**'
}

tasks.withType(FindBugs) {
  exclude '**/org/jsense/serialize/protobuf/gen/*'
}

findbugs {
  excludeFilter = file("$projectDir/config/findbugs/excludeFilter.xml")
}

<?xml version="1.0" encoding="UTF-8"?>
<FindBugsFilter>
  <Match>
    <Package name="org.jsense.serialize.protobuf.gen"/>
  </Match>
</FindBugsFilter>

def excludePattern = 'org/jsense/serialize/protobuf/gen/'
def excludePatternAntStyle = '**/' + excludePattern + '*'
tasks.withType(FindBugs) {
    classes = classes.filter {
        !it.path.contains(excludePattern)
    }
}
tasks.withType(Checkstyle) {
    exclude excludePatternAntStyle
}
tasks.withType(Pmd) {
    exclude excludePatternAntStyle
}

Answer 1

sourcetask#exclude筛选源文件。但是，FindBugs主要对类文件进行操作，您还必须对类文件进行筛选。尝试以下操作：

tasks.withType(FindBugs) {
    exclude '**/org/jsense/serialize/protobuf/gen/*'
    classes = classes.filter { 
        !it.path.contains(new File("org/jsense/serialize/protobuf/gen/").path) 
    }
}

PS：在FindBugs的情况下，过滤源文件可能没有区别（因此没有必要）。（不过我还没试过。）