如何使用JPA查询将数据插入数据库？

Question

我的准备好的语句有问题，但我无法找出错误所在。我正在尝试将URI链接插入数据库。

 @Repository
 public interface LoggerDao extends CrudRepository<Logger, Long> {
 @Query("select t from Logger t where t.user.id=?#{principal.id}")
 List<Logger> findAll();

@Modifying
@Query(value = "insert into Logger t (t.redirect, t.user.id) VALUES (:insertLink,?#{principal.id})", nativeQuery = true)
@Transactional
void logURI(@Param("insertLink") String insertLink);

错误

    2017-03-11 19:52:59.157  WARN 65154 --- [nio-8080-exec-8] o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: 42001, SQLState: 42001
2017-03-11 19:52:59.157 ERROR 65154 --- [nio-8080-exec-8] o.h.engine.jdbc.spi.SqlExceptionHelper   : Syntax error in SQL statement "INSERT INTO LOGGER T[*] (T.REDIRECT, T.USER.ID) VALUES (?,?) "; expected "., (, DIRECT, SORTED, DEFAULT, VALUES, SET, (, SELECT, FROM"; SQL statement:
insert into Logger t (t.redirect, t.user.id) VALUES (?,?) [42001-190]
2017-03-11 19:52:59.181 ERROR 65154 --- [nio-8080-exec-8] o.a.c.c.C.[.[.[/].[dispatcherServlet]    : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.InvalidDataAccessResourceUsageException: could not prepare statement; SQL [insert into Logger t (t.redirect, t.user.id) VALUES (?,?)]; nested exception is org.hibernate.exception.SQLGrammarException: could not prepare statement] with root cause

org.h2.jdbc.JdbcSQLException: Syntax error in SQL statement "INSERT INTO LOGGER T[*] (T.REDIRECT, T.USER.ID) VALUES (?,?) "; expected "., (, DIRECT, SORTED, DEFAULT, VALUES, SET, (, SELECT, FROM"; SQL statement:
insert into Logger t (t.redirect, t.user.id) VALUES (?,?) [42001-190]
    at org.h2.engine.SessionRemote.done(SessionRemote.java:624) ~[h2-1.4.190.jar:1.4.190]
    at org.h2.command.CommandRemote.prepare(CommandRemote.java:68) ~[h2-1.4.190.jar:1.4.190]
    at org.h2.command.CommandRemote.<init>(CommandRemote.java:45) ~[h2-1.4.190.jar:1.4.190]
    at org.h2.engine.SessionRemote.prepareCommand(SessionRemote.java:494) ~[h2-1.4.190.jar:1.4.190]
    at org.h2.jdbc.JdbcConnection.prepareCommand(JdbcConnection.java:1188) ~[h2-1.4.190.jar:1.4.190]
    at org.h2.jdbc.JdbcPreparedStatement.<init>(JdbcPreparedStatement.java:72) ~[h2-1.4.190.jar:1.4.190]
    at org.h2.jdbc.JdbcConnection.prepareStatement(JdbcConnection.java:276) ~[h2-1.4.190.jar:1.4.190]
    at org.apache.tomcat

Answer 1

有一种方法可以使用obj（非本机）查询（使用@Query

@Repository
public interface DualRepository extends JpaRepository<Dual,Long> {
    @Modifying
    @Query("insert into Person (id,name,age) select :id,:name,:age from Dual")
    public int modifyingQueryInsertPerson(@Param("id")Long id, @Param("name")String name, @Param("age")Integer age);
}

下面是一个链接，它在底部显示了数据库的支持选择没有from子句的stmts：http://modern-sql.com/use-case/select-without-from

Answer 2

我设法解决了这个问题。我在参数中添加了一个id，以便我可以使用控制器中的主体传入用户的id。

@Repository
public interface LoggerDao extends CrudRepository<Logger, Long> {
    @Query("select t from Logger t where t.user.id=?#{principal.id}")
    List<Logger> findAll();

    @Modifying
    @Query(value = "insert into Logger (redirect,user_id) VALUES (:insertLink,:id)", nativeQuery = true)
    @Transactional
    void logURI(@Param("insertLink") String insertLink, @Param("id") Long id);