在Firestore云函数中创建文档时，我希望进行查询以获得兼容的文档，然后向它们发送通知

Question

更多解释：

null

exports.NewRequestCreated = functions.firestore.document('/Requests/{documentId}').onWrite(event => {
// Get an object with the current document value

var myRequest = event.data.data();

// Get an object with the previous document value (for update or delete)
// Note that previous will be null if no old value exists.
if (event.data.previous) {
  var oldDocument = event.data.previous.data();
}

//Get list of donors that can match this request
var compatibleTypesArray = getCompatibeUsers(myRequest.Type);
var matchingUsersArray = [];


var usersRef = functions.firestore.document('/Users');//functions.firestore.document('/Users');
var matchingUsersQuery = usersRef.where('city', '==', myRequest.city).where('type', '==', myRequest.type)
var user = matchingUsersQuery.get()
.then(snapshot => {
    snapshot.forEach(doc => {
        console.log(doc.id, '=>', doc.data());
    });
})
.catch(err => {
    console.log('Error getting documents', err);
});

TypeError：usersRef.where在导出时不是函数。EXPORTS.NewRequestCreated在Object上创建了created.functions.firestore.document.onwrite.event(/user_code/index.js:45:40)。(/user_code/node_modules/firebase-functions/lib/cloud-functions/lib/cloud-functions.js:59:27)在next（本机）在/user_code/node_modules/firebase-functions/lib/cloud-functions.js:28:71在__awaiter(/user_code/node_modules/firebase-functions/lib/cloud-functions.js:24:12)在

Answer 1

usersref是一个文档。正如您将在API文档中看到的，该类上没有where()方法。

也许您打算使用collection（）获取一个CollectionReference对象，然后可以使用where（）方法查询文档。

functions.firestore.collection('/Users');