如何创建“打开方式”对话框？

Question

我做了一个程序来搜索.txt文件。

如果我单击一个文件，这意味着“打开”对话框应该出现，该对话框将包含所有已安装程序的列表。

  public File[] finder( String dirName)
  {
      // Create a file object on the directory.
      File dir = new File(dirName);
      // Return a list of all files in the directory.
      return dir.listFiles(new FilenameFilter();
  } 

  public boolean accept(File dir, String filename)
  { 
      return filename.endsWith(".txt");
  } 

我可以使用什么Java代码来使“打开时”对话框出现？

Answer 1

为此，您应该使用filechooser。看看这里：

//Create a file chooser
final JFileChooser fc = new JFileChooser();
...
//In response to a button click:
int returnVal = fc.showOpenDialog(aComponent);


public void actionPerformed(ActionEvent e) {
    //Handle open button action.
    if (e.getSource() == openButton) {
        int returnVal = fc.showOpenDialog(FileChooserDemo.this);

        if (returnVal == JFileChooser.APPROVE_OPTION) {
            File file = fc.getSelectedFile();
            //This is where a real application would open the file.
            log.append("Opening: " + file.getName() + "." + newline);
        } else {
            log.append("Open command cancelled by user." + newline);
        }
   } ...
}