想知道如何在java中打印方法的确切返回值吗？[关闭]

Question

我在尝试这个问题，我理解的逻辑，但是当我运行代码时，返回值被打印为0而不是2，我可以知道我在这里做错了什么吗。我刚刚开始竞争性编程。

问题:

//Given an array of integers, any array element can be moved to the end in one move. Determine minimum numbers of moves required to sort the array in ascending order.


// Eg: [1,3,2]
// Output: 1
// Explanation: 3 to end
// Eg: [5,1,3,2]
// Output: 2
// Explanation: 1) 3 to end
//           2) 5 to end
// Eg: [ 1,3,2,5]
// Output: 2
// Explanation: 1) 3 to end
//           2) 5 to end

package OA_Questions;

import java.util.Arrays;

public class SortAnArray {
        public int Solution(int[] arr){

            int[] expectedArray = new int[arr.length] ;
            System.arraycopy(arr, 0, expectedArray, 0,arr.length);
            int j =0, n = arr.length, ans =n;

            for(int k :arr){
                if(k == expectedArray[j]){
                    j++;
                    ans--; 
                }

            }
            return ans; 
        }    
    public static void main(String[] args) {
       

            int[] arr = new int[] {5,1,3,2};
            System.out.println(Arrays.toString(arr));
            SortAnArray soa = new SortAnArray();
            System.out.println(soa.Solution(arr));
    }
} 

Answer 1

预期数组应该在您的逻辑中排序。将此放在每个循环之前

Arrays.sort(expectedArray);