Django REST框架-针对URL进行筛选

Question

我将Django REST框架工具包与Django1.11一起使用，并尝试根据URL过滤结果。以下是我的设置：

models.py：

from django.db import models

class Package(models.Model):
name = models.CharField(max_length=255, unique=True)
def __str__(self):
    return self.name

from rest_framework import serializers
from .models import Package

class PackageSerializer(serializers.ModelSerializer):
      class Meta:
            model = Package
            fields = ('name',)

from rest_framework import viewsets
from .models import Package
from .serializers import PackageSerializer

class PackageViewSet(viewsets.ReadOnlyModelViewSet):
     serializer_class = PackageSerializer
     queryset = Package.objects.all()

from django.conf.urls import url, include
from django.contrib import admin
from rest_framework import routers

router = routers.DefaultRouter()
router.register(r'package', views.PackageViewSet)

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^api/v1/', include(router.urls)),
]

http://127.0.0.1:8000/api/v1/package/1/

我希望通过我的包模型的name字段来过滤结果，而不是使用以下内容：

http://127.0.0.1:8000/api/v1/package/basic/

我怎么才能做到这一点呢？

Answer 1

在viewset中设置lookup_field属性，请参阅文档。

class PackageViewSet(viewsets.ReadOnlyModelViewSet):
    serializer_class = PackageSerializer
    queryset = Package.objects.all()
    lookup_field = 'name'