显示井字游戏应用的结果

Question

我目前正在编写一个创建井字游戏的程序。目前的应用程序有两个人互相对战，轮流输入行号和列号。这个程序的主要问题是我无法让它显示一个人赢或输或两个玩家平局的结果。如果有人对我如何解决这个问题有任何建议，那就太好了。再次感谢您的时间。

import java.util.Scanner;

public class ticTacToeApp {
    // 1. GAME CONSTANTS
    static final int WIN = 1;
    static final int LOSE = 0;
    static final int TIE = 2;
    static final int GAME_IN_PROGRESS = 3;
    static final String PLAYER = "X";
    static final String OPPONENT = "O";
    static final String EMPTY = " ";
    // 2. INPUT STREAM
    static Scanner in;

    public static void main(String[] args) {
        // 3. BUILD THE TIC TAC TOE 3X3 BOARD OF STRINGS
        String[][] board = { { EMPTY, EMPTY, EMPTY }, { EMPTY, EMPTY, EMPTY },{EMPTY, EMPTY, EMPTY } };
        // 4. INSTANTIATE THE SCANNER FOR INPUT
        in = new Scanner(System.in);
        // 5. GAME ENGINE
        drawBoard(board);
        int moveResult = GAME_IN_PROGRESS; // STATUS OF THE GAME AND AFTER A
                                            // MOVE
        while (moveResult == GAME_IN_PROGRESS) {
            // PLAYER MOVES AND BOARD IS CHECKED FOR A RESULT
            getMove(board, PLAYER, in);
            drawBoard(board);
            if (moveResult != GAME_IN_PROGRESS)
                break;

            // OPPONENT MOVES AND THE BOARD IS CHECKED FOR A RESULT
            getMove(board, OPPONENT, in);
            drawBoard(board);
            moveResult = boardResults(board);
        }
        // 6. ONCE THE GAME HAS ENDED, DISPLAY IT IS AS A WIN, LOSE, OR TIE.
        if (moveResult == WIN)
            System.out.println("You win.");
        else if (moveResult == LOSE)
            System.out.println("You lost.");
        else
            System.out.println("You tied.");
    }

    public static int boardResults(String[][] board) {
        // TASK 1: BUILD AN ARRAY CONTAINING ALL THE ROW, COLUMN, AND
        // DIAGONAL STRING ARRANGEMENTS ON THE CURRENT
        // TIC TAC TOE BOARD.
        String[] waysToWin = new String[8];
        int i = 0; // INDEX TO wayToWin
        for (int r = 0; r < 3; r++) {
            String str = " ", stc = " ";
            for (int c = 0; c < 3; c++) {
                str += board[r][c];
                stc += board[c][r];
            }
            waysToWin[i++] = str;
            waysToWin[i++] = stc;

            // ADD 2 DIAGONALS
            waysToWin[i++] = board[0][0] + board[1][1] + board[2][2];
            waysToWin[i++] = board[0][2] + board[1][1] + board[2][0];
            // TASK 2. CHECK IF ANY OF THESE ARRANGEMENTS CONTAIN A WINNING
            // "XXX" OR
            // "OOO"
            // NOTE: AN "XXX" IS WIN AND AN "OOO" IS LOSE.
            for (int p = 0; p < 8; p++) {
                if (waysToWin[p].equals("XXX"))
                    return WIN;
                if (waysToWin[p].equals("OOO"))
                    return LOSE;
                // TASK 3. CHECK IF THE BOARD IS FULL (TIE) OR IF THE GAME IS
                // STILL IN
                // PROGRESS
                if (board[0][0] == EMPTY || board[0][1] == EMPTY || board[0][2] == EMPTY || board[1][0] == EMPTY
                        || board[1][1] == EMPTY || board[1][2] == EMPTY || board[2][0] == EMPTY || board[2][1] == EMPTY
                        || board[2][2] == EMPTY)
                    return GAME_IN_PROGRESS;

            }
        }
        return i;

    }

    public static void drawBoard(String[][] board) {
        for (int row = 0; row < board.length; row++) {
            System.out.println("___________");
            for (int col = 0; col < board[row].length; col++) {
                System.out.print("|" + board[row][col] + " ");
            }
            System.out.println("| ");
        }
        System.out.println("___________");
    }

    public static void getMove(String[][] board, String whoseMove, Scanner in) {
        int[] xy = new int[2];
        for (;;) {
            System.out.print("You are " + whoseMove + ". ");
            System.out.println("Enter the row and column of your move: ");
            xy[0] = in.nextInt();
            xy[1] = in.nextInt();
            if (board[xy[0]][xy[1]].equals(EMPTY))
                break;
            System.out.println("You must choose an empty space.");
        }
        board[xy[0]][xy[1]] = whoseMove;
    }
}

Answer 1

我将使用一个单维数组作为棋盘，并创建一个获胜组合数组，索引到棋盘中。然后循环通过获胜的组合，计算X和O。如果你有3个，那么宣布一个获胜者。下面是一段演示：

public class ticTacToeApp {
  static final String X = "X";
  static final String O = "O";
  static final String N = " ";

  public static void main(String[] args) {
    String[] board = { X,X,O,
        N,O,N,
        O,N,N };

    // combinations to win: 
    int[][] wins = { {0,1,2}, {3,4,5}, {6,7,8}, {0,3,6}, {1,4,7}, {2,6,8}, {0,4,8}, {2,4,6} };

    // count x's and o's to win
    int x=0, o=0;

    // find the winner by indexing the board array from the combinations to win array
    // In each combination to win, if all 3 are X's or O's, declare a winner

    for(int i=0; i<8; i++) {
      x=0; o=0;
      for(int j=0;j<3;j++) {
        if (board[wins[i][j]] == X) x++;          
        if (board[wins[i][j]] == O) o++;    
      }
      if (o==3 || x==3) 
        System.out.println(((x==3) ? "X" : "O") + " wins");
    }
  }
}