从两个不同的IP连接到服务器不起作用（聊天应用程序）

Question

我构建了一个客户端/服务器聊天应用程序，其中服务器正在侦听IP号码127.0.0.1和端口1212，客户端应该连接到该IP

问题-按以下顺序：

>

我在计算机上运行服务器，正在侦听 （127.0.0.1

我还在我的计算机上运行一个客户端（与#1相同的计算机），它成功地连接到服务器（127.0.0.1

我正在从不同的IP运行另一个客户端，但在尝试连接到服务器时（127.0.0.1

我不明白为什么…这是代码：

服务器端:

public partial class ServerForm : Form
{
    private TcpListener m_tcpServer;
    private TcpClient m_tcpClient; 
    private Thread th;
    private ServerNotifier m_chatDialog;
    private List<ServerNotifier> m_formArray = new List<ServerNotifier>();
    private ArrayList m_threadArray = new ArrayList();
    public delegate void ChangedEventHandler(object sender, EventArgs e);
    public event ChangedEventHandler m_Changed;
    public delegate void SetListBoxItem(String str, String type); 


    // some code 

   public void StartListen() 
    {             
        IPAddress localAddr = IPAddress.Parse("127.0.0.1");
        m_tcpServer = new TcpListener(localAddr, Int32.Parse(tbPortNumber.Text));
        m_tcpServer.Start();

        // Keep on accepting Client Connection
        while (true)
        {               
            // New Client connected, call Event to handle it.
            Thread t = new Thread(new ParameterizedThreadStart(NewClient));
            m_tcpClient = m_tcpServer.AcceptTcpClient();
            t.Start(m_tcpClient);                 
        }
    }




}

服务器的消息......

客户端 ：

public partial class ClientForm : Form
{

    // to know when a button was clicked
    private bool m_connectionEstablished = false;
    private bool m_enterKeyPressed = false;
    private bool m_notRunning = false;        // flip this when the server is not running
    private NetworkStream m_ns = null;
    private StateObject m_state = null;
    private TcpClient m_clientTcpConnection = null;

    // ip and m_username entered by the client
    private String m_ipNumberString = String.Empty;
    private String m_username = String.Empty;
    private int m_port = 0;

    public bool StartTheClient(int m_port)
    {
        byte[] data = new byte[1024];
        string inputFromClient = "";            
        string portString = "";

        try
        {
            // "127.0.0.1"
            this.m_clientTcpConnection = new TcpClient(this.m_ipNumberString , this.m_port);
        }

        catch (Exception e)
        {
            // this.rtbClientChat.SelectionColor = Color.LimeGreen;
            this.m_notRunning = true;  // m_clientTcpConnection is not running
            MessageBox.Show("The server is currently not running , try again later!");
            // connection failed
            return false;  
        }

        this.rtbClientChat.SelectedText = "Connected to the Server...";
        String local_IP = ((IPEndPoint)m_clientTcpConnection.Client.LocalEndPoint).Address.ToString();
        String local_Port = ((IPEndPoint)m_clientTcpConnection.Client.LocalEndPoint).Port.ToString();
        this.rtbClientChat.SelectedText = "\nConnected on IP address " + local_IP + " and Port " + local_Port;
        this.rtbClientChat.SelectedText = "\nEnter a message to send to the Server";


        this.m_ns  =  m_clientTcpConnection.GetStream();
        this.m_state = new StateObject();
        this.m_state.workSocket = m_clientTcpConnection.Client;
        this.m_clientTcpConnection.Client.BeginReceive(m_state.buffer, 0, StateObject.BufferSize, 0,
                    new AsyncCallback(OnReceive), m_state);
        // connection established successfully
        this.m_connectionEstablished = true;
        return true;

    }





   /// <summary>
    /// connet/disconnect
    /// </summary>
    /// <param name="sender"></param>
    /// <param name="e"></param>
    private void checkBox1_CheckedChanged(object sender, EventArgs e)
    {
        if (this.connectionLabel.Checked == true)
        {
            // then the user checked the "connet/disconnect" checkbox 
            // now check if the user also filled the m_port number 

            try
            {                    
                // trying to check if the user entered something is the m_port box
                // grab port number 
                m_port = Int32.Parse(this.boxPortNumber.Text);
                m_ipNumberString = this.ipBoxNumber.Text;

                // grab IP number
                if (m_ipNumberString == string.Empty)
                {
                    MessageBox.Show("Please enter a valid IP Number!");
                    this.connectionLabel.Checked = false;
                    return;
                }

                // grab username
                this.m_username = this.usernameBox.Text;
                if (this.m_username == string.Empty)
                {
                    MessageBox.Show("Please enter a Username!");
                    this.connectionLabel.Checked = false;
                    return;
                }
                StartTheClient(m_port);

            }
            catch (Exception exp)
            {
                if (this.m_notRunning == true)    
                {
                    // then the user tried to initiate connection
                    // while the m_clientTcpConnection is disconnected 
                    this.m_notRunning = false;
                }
                else
                {
                    // the user didn't put anything in the m_port box
                    MessageBox.Show("Please enter a Port number !");
                    this.connectionLabel.Checked = false;
                }

            }
        }
    }

它的winform:

任何想法为什么会发生这种情况？

非常感谢！

Answer 1

每个设备都有自己的本地主机（127.0.0.1）。

您不能连接到另一台PClocalhost（127.0.0.1），因此您的服务器应该有IP，例如192.168.0.1，该IP具有可从另一台PC访问的指定端口。

如果不是，每次它只会尝试连接到自己的本地主机！

通常，我们只使用localhost在内部测试我们的网络程序。但是，如果您想在本地主机上进行外部测试，则不会成功。

Answer 2

127.0.0.1 在计算机网络中，本地主机是指此计算机。因此，如果您在另一台PC上运行客户端，它将尝试连接到该PC上的服务器，但您的服务器位于另一台PC上。将客户端 IP 设置为您拥有服务器的 IP。

127.0.0.1

如果您在服务器上有多个网络接口，您应该像这样启动您的侦听器，有关更多详细信息，请访问以下链接:

m_tcpServer = new TcpListener(IPAddress.Any, Int32.Parse(tbPortNumber.Text));

TcpListener构造函数

Answer 3

127.0.0.1是本地主机。您应该指定网络中服务器的IP。通过在命令提示符下运行ipconfig，您可以轻松找到服务器的IP。并且侦听器也应该在该IP地址上启动。