使用筛选的订阅从主题检索Azure服务总线消息

Question

我试图遵循Mark Heath的控制台应用程序示例，使用筛选后的订阅检索服务总线主题消息。但是，我实际上无法检索实际筛选的消息(Filtered1、Filtered2)。消息确实会被使用，但我无法查看它们，因为代码从未像处理非过滤消息（AllMessages）那样进入回调函数。对我错过了什么有什么想法吗？

发件人代码

var body = "Hello World";
var message1 = new BrokeredMessage(body);
message1.Properties["From"] = "Ian Wright";

var message2 = new BrokeredMessage("Second message");
message2.Properties["From"] = "Alan Smith";
message2.Label = "important";

var message3 = new BrokeredMessage("Third message");
message3.Properties["From"] = "Kelly Smith";
message3.Label = "information";

var client =  TopicClient.CreateFromConnectionString(servicebusConnectionString, topicName);
 client.Send(message1);
 client.Send(message2);
 client.Send(message3);

接收机代码

const string topicName = "rightangle";
const string subscriptionName = "AllMessages";
const string sub1Name = "Filtered1";
const string sub2Name = "Filtered2";

NamespaceManager namespaceManager = NamespaceManager.CreateFromConnectionString(connectionString);

if (!namespaceManager.SubscriptionExists(topicName, subscriptionName))
{
    namespaceManager.CreateSubscription(topicName, subscriptionName);
}
if (namespaceManager.SubscriptionExists(topicName, sub1Name))
{
    Console.WriteLine("Deleting subscription {0}", sub1Name);
    namespaceManager.DeleteSubscription(topicName, sub1Name);
}
Console.WriteLine("Creating subscription {0}", sub1Name);
namespaceManager.CreateSubscription(topicName, sub1Name, new SqlFilter("From LIKE '%Smith'"));

if (namespaceManager.SubscriptionExists(topicName, sub2Name))
{
    Console.WriteLine("Deleting subscription {0}", sub2Name);
    namespaceManager.DeleteSubscription(topicName, sub2Name);
}
Console.WriteLine("Creating subscription {0}", sub2Name);
namespaceManager.CreateSubscription(topicName, sub2Name, new SqlFilter("sys.Label='important'"));

var options = new OnMessageOptions();

var subClient =                    SubscriptionClient.CreateFromConnectionString(connectionString, topicName, subscriptionName);
subClient.OnMessage(m => MessageReceived(subscriptionName, m), options);

var subClient1 =                    SubscriptionClient.CreateFromConnectionString(connectionString, topicName, sub1Name);

subClient1.OnMessage(m => MessageReceived(sub1Name, m), options);

var subClient2 =                    SubscriptionClient.CreateFromConnectionString(connectionString, topicName, sub2Name);

subClient2.OnMessage(m => MessageReceived(sub2Name, m), options);

private static void MessageReceived(string subscriptionName, BrokeredMessage message)
{
   Console.WriteLine("{0} '{1}' Label: '{2}' From: '{3}'", subscriptionName,
            message.GetBody<string>(),
            message.Label,
            message.Properties["From"]);

}

Answer 1

密码没问题。运行此示例后，allmessages包含三条消息，filtered1包含两条消息，filtered2包含一条消息。您确定没有另一个使用代码的实例正在运行并检索这些消息吗？

allmessages有一个默认的SQL筛选器，因此它是一个“catch-all”订阅。筛选不会对它产生影响，它应该获得发送到rightangle主题的任何消息。如果在它下面没有看到任何消息，那么要么消息已被使用，要么应用程序正在重新构建实体，从而删除所有消息。

尝试更改接收方代码不删除实体，而只接收。并修改发件人以确保实体存在,如果不存在,则创建实体,但不删除实体。或者，您可以将这两个代码（首先是接收者代码，然后是发送者代码）进行cobine，您将看到消息。问题只在于如何管理（删除）实体。