while循环中的多个条件以及在满足条件时查找索引

Question

我需要两种while循环的帮助。

while playerA < 10 or playerB < 10 and abs(playerA-playerB) < 3:

list = [4,1,6,3,6,5,2]
threshold = 10

Answer 1

1）括号帮助但while循环时，布尔逻辑可能会让人混淆。最好的方法是将其分成几个部分。要使循环停止，在以下情况下，两边必须都是false，因此一个播放器必须超过10且差值必须大于3。如果您仍然有问题，您可以在该循环中执行If，因为至少逻辑不是反向的。

while (playerA < 10 and playerB < 10) or abs(playerA-playerB) < 3:

另一个选择（可能对您有帮助）是打破检查逻辑，这样事情就不会倒退：

def can_continue(playerA, playerB):
    if (playerA > 10 or playerB > 10) and abs(playerA - playerB) >= 3:
        return False
    return True

然后执行：

while can_continue(playerA, playerB):

2）环路可能有点棘手，但您只需短路即可。

my_list = [4,1,6,3,6,5,2] # list wasn't a good variable name.
threshold = 10
score_sum = 0
for index, ele in enumerate(my_list):
    if score_sum + ele > threshold:
        break
    score_sum += ele
print(score_sum) # 5
print(index) # We stopped at index 2
print(my_list[:index]) # We can splice with that index [4, 1]