php准备语句SQLSTATE[42000]:语法错误或访问冲突：1064

Question

$street = 'astreet';
$lname = 'alname';
$fname = 'afname';
$list = '1,2,3,4,5';

   $var = 'admin';  

   $db = new PDO("mysql:dbname=customers;host=localhost",$var,$var);

   $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);

$sql = "SELECT * FROM `table` WHERE `id` in ($list) AND `first_name` LIKE :fname AND `last_name` LIKE :lname AND `street_name` LIKE :street";

   $stmt = $db->prepare($sql);

   $stmt->execute(array(':street' => $street));
   $stmt->execute(array(':fname' => $fname));
   $stmt->execute(array(':lname' => $lname));

   $result = $db->query($sql);



foreach ($result as $row) {

        echo $row['post_code'];

              }

是否有代码缺失/不正确？

谢谢

Answer 1

$stmt = $db->prepare($sql);

$stmt->execute(array(':street' => $street));
$stmt->execute(array(':fname' => $fname));
$stmt->execute(array(':lname' => $lname));

您将运行同一个查询三次，每次都使用不同的参数。您需要按照以下方式运行查询：

$stmt = $db->prepare($sql);

$stmt->execute(array(':street' => $street, ':fname' => $fname, ':lname' => $lname));

并一次性传递所有三个参数。

编辑添加：

$stmt = $db->prepare($sql);

$stmt->bindParam(':street', $street);
$stmt->bindParam(':fname', $fname);
$stmt->bindParam(':lname', $lname);

$stmt->execute();

$sql = "SELECT * FROM `table` WHERE `id` in ($list) AND `first_name` LIKE ? AND `last_name` LIKE ? AND `street_name` LIKE ?";
$stmt = $db->prepare($sql);

$stmt->execute(array($fname, $lname, $street));