我需要关于如何将两个具有相同键的值从json格式解析为java映射的建议

Question

我正在将ldif属性从LDAP读取到我的java程序中,我最初的想法是将这些属性放入映射中,然后从映射中解析它们,但我发现,有一个属性叫做“DepartmentNumber”,它包含两个json格式值,

departmentNumber: {"sid":"729999","uid":501,"name":"tebase","role":"managers","title":"sales","groups":["others"]}
departmentNumber: {"sid":"724605","uid":37,"name":"tebase","role":"managers","title":"develope","groups":["leaders"]}

所以我用map把它们放进去，下面显示的一些代码，

但我的方法只能检索第一个json值,即包含{“sid”：“729999”}的值,而不包含{“sid”：“724605”}的第二个值,

我观察到的程序日志是：

2019 22:30:58,237 authentication.mzauth   authentication.mzauth.doAuthenticate(mzauth.java:44)  
{"uid":"brucelee","mail":"[e-mail]","displayName":"Bruce Lee","givenName":"Bruce Lee","departmentNumber":"{\"sid\":\"729999\",\"uid\":501,\"name\":\"teabas\",\"role\":\"managers\",\"title\":\"sales\",\"groups\":[\"others\"]}","objectClass":"inetOrgPerson","description":"Bruce Lee","sn":"Bruce Lee","cn":"Z39414","department":"000000","info":"2006/02/12"}   

2019 22:30:58,247 services.LdapService services.LdapService.getUser(LdapService.java:251)
ldap user：{"username":"brucelee","fullname":"Bruce Lee","email":"[e-mail]","departmentid":"729999","titles":[{"schoolid":"729999","titles":["managers","sales"]}],"cloudroles":{"usage":"clouddev","roles":[{"appname":"mail","departmentid":"729999","titles":["managers","sales"]}]},"guid":"c00d5ba660145307c84f2c1e1c557e4ededaf1830029d40aa5b244027","pid":"Z39414","openid":"http://openid.macom/brucelee"}  

Z39414,Managers,developer.alle.com dn:cn=Z39414,ou=Managers,dc=developer,dc=alle,dc=com uid：brucelee用户密码：qwdmsdierf mail：[e-mail]信息：2006/02/12 sn：Bruce Lee部门号：{“sid”：“729999”,“uid”：501,“name”：“tebase”,“role”：“Managers”,“title”：“sales”,“groups”：[“others”]}部门号：{“sid”：“724605”,“uid”：37

搜索结果搜索：2结果：0成功NumResponses：2 NumEntries：1

我的问题是，我如何将两个json值都放入我的map中，或者我对map的用法是错误的，有更好的方法来处理这种情况？

public DataModel getUser(String uid, String passwd, String role, DataModel   user) throws Exception {
private Map<String, String> map = null;
   if (role.equals("managers")) {
            map = Ldap.getAttrubites(ldapurl, uid, passwd);
            List<Titles> titlesArray = new ArrayList<>();
            List<Roles> rolesArray = new ArrayList();
            map.forEach((key, value)
                    -> {logger.info("{} - {}", key, value); });
     if (key.equals("departmentNumber")) {
                List<StringModel> model = map.get("departmentNumber")).get();
                model.stream().forEach(k -> {
                for (int i = 0; i < model.size(); i++) {
                            Titles titles = new Titles();
                            List<String> titleList = new ArrayList<>();
                            String userid = model.get(i).getUid();
                            String mtitle = model.get(i).getRole();
                            String subtitle = model.get(i).getTitle();
                            titleList.add(mtitle);
                            titleList.add(subtitle);
                            titles.setSchoolid(schoolid);
                            titles.setTitles(titleList);
                            titlesArray.add(titles);

                 ........ });}
                 user.setTitles(titlesArray);
                 .........;
    } return user;
    }

Answer 1

java.util.map 接口只为每个键保留一个值。如果要为每个键保存多个值，则需要为v部分指定一个集合类。例如，如下所示。

Map<String, List<String>> map = ...

Java EE API中定义的javax.ws.rs.core.multivaluedMap接口就是一个实现您想要实现的功能的示例。