选择JFXCombobox项并发送到新Combobox

Question

我使用JFoenix库来创建组合框。

“boxLeague。getSelectionModel（）。选择EditeProperty（）。addListener（（可观察、旧值、新值）-

public class Controller implements Initializable {

@FXML
private JFXComboBox<String> boxLeague;

@FXML
private JFXComboBox<String> boxTeams;

@FXML
private JFXComboBox<String> boxPlayers;


ObservableList<String> listLeagues = FXCollections.observableArrayList(
        "Bundesliga", "La Liga", "Ligue 1", "Premier League", "Serie A", "Champions League", "Europa League");

ObservableList<String> listPremierLeague = FXCollections.observableArrayList(
        "Arsenal", "Bournemouth", "Brighton", "Burnley", "Chelsea", "Crystal Palace", "Everton");




@Override
public void initialize(URL location, ResourceBundle resources) {

    boxLeague.setItems(listLeagues);
    boxLeague.getSelectionModel().selectedItemProperty().addListener((observable, oldValue, newValue) -> boxTeams.setItems(listPremierLeague));
}

}

Answer 1

在你的听众中，你需要找出哪个联赛被选中，并相应地设置boxTeams的项目。

boxLeague.getSelectionModel().selectedItemProperty().addListener(
  (observable, oldValue, newValue) -> { 
      if (newValue.equals("Premier League")) {
          boxTeams.setItems(listPremierLeague));
      } // else if ... (or use a switch-case here)
  }
);

请注意，如果您不为联盟和团队使用Strings，而是创建自己的类，那么这可以进一步改进。