在具有卡片布局的JPanel中两个JPanel之间的交换

Question

我试图让两个jpanels通过这些特定面板上的按钮交换，我不想让普通的按钮在两个面板上都像普通的卡片布局使用重复在两个面板上。我已经尝试有一个按钮称为‘添加’在主面板上导致下一页和按钮在下一页称为‘返回’导致主面板。然而，出于某种原因，它不起作用。我不希望JFrame上有两个JPanel，因为稍后我将把JPanel添加到选项卡式窗格中。以下是我已经拥有的：

import java.awt.CardLayout;
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;

public class Controller extends JPanel {

    private static Controller instance = new Controller();

    JPanel cards;
    Main mainPanel;
    NextPage nextPage;

    public Controller() {
        setLayout(new BorderLayout());
        setSize(810, 510);
        cards = new JPanel(new CardLayout());

        mainPanel = new Main();
        nextPage = new NextPage();
        cards.add(mainPanel, "Main");
        cards.add(nextPage, "Next");
        add(cards);
        setVisible(true);
    }

    private static void createAndShowGUI() {
        JFrame frame = new JFrame("MainPanel");
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        Controller con = new Controller();
        frame.getContentPane().add(con);
        frame.setSize(800, 600);
        frame.setVisible(true);
    }

    public static void main(String[] args) {
        javax.swing.SwingUtilities.invokeLater(new Runnable() {
            public void run() {
                createAndShowGUI();
            }
        });
    }


    public void changeCard(String card) {
        CardLayout cl = (CardLayout) (cards.getLayout());
        cl.show(cards, card);
    }

    public static Controller getInstance() {
        return instance;
    }
}

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.event.*;
import java.util.*;

public class Main extends JPanel implements ActionListener {

    private JButton search, add, delete;
    private JTextField textField;

    public Main() {

        search = new JButton("Search");
        add = new JButton("Add");
        delete = new JButton("Delete");
        textField = new JTextField(20);
        add.addActionListener(this);
        delete.addActionListener(this);
        setLayout(new BorderLayout());
        JPanel top = new JPanel();
        top.add(search);
        add(top, BorderLayout.NORTH);
        JPanel bottom = new JPanel();
        bottom.add(add);
        bottom.add(delete);
        add(bottom, BorderLayout.SOUTH);
        setVisible(true);
        setSize(400, 500);
    }

    public void actionPerformed(ActionEvent e) {
        if (e.getSource() == add) {
            Controller.getInstance().changeCard("Next");
        } else if (e.getSource() == delete) {
           System.out.println("do something");
        }
    }

}

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.event.*;
import java.util.*;

public class NextPage extends JPanel implements ActionListener {

    private JButton back;
    private JTextField textField;

    public NextPage() {
        back = new JButton("Back");
        textField = new JTextField(20);
        back.addActionListener(this);
        setLayout(new BorderLayout());
        add(back);
        setVisible(true);
        setSize(400, 500);
    }

    public void actionPerformed(ActionEvent e) {
        if (e.getSource() == back) {
            Controller.getInstance().changeCard("Next");
        }

    }
}

Answer 1

更改控制器，如下所示：

private static Controller instance;

...

private static void createAndShowGUI() {
    JFrame frame = new JFrame("MainPanel");
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    instance = new Controller();
    frame.getContentPane().add(instance);
    frame.setSize(800, 600);
    frame.setVisible(true);
}

您实际上在Controller的实例上创建了所有内容并显示了它，但使用了另一个实例来管理事件。对控制器构造函数的多次调用应该敲响了铃声，因为您只需要一个控制器。