如何创建接受泛型对象的JAXB封送程序

Question

基本上，我要做的是创建一个封送器，它可以接收我给它的任何类对象，例如，car对象或person对象，并且它必须返回一个XML字符串。

 public <T> String CreateXML(T objToSerialize)
    {
        String xml = "";
        try 
        {           

        JAXBContext context = JAXBContext.newInstance(objToSerialize.getClass());
        Marshaller marshaler = context.createMarshaller(); 
        StringWriter writer = new StringWriter();
        marshaler.marshal(objToSerialize.getClass(),writer);
        xml = writer.toString();
            System.out.println(xml);
            return xml;
        } catch (Exception e) {
            System.out.println(e.getMessage());
        }
        return xml;
    }

警告：发生了非法的反射访问操作

Answer 1

在代码中，封送的是objectToSerialize的类，而不是对象本身。您可以更改这一行

 marshaler.marshal(objToSerialize.getClass(),writer);
 //to
 marshaler.marshal(objToSerialize,writer);

或者尝试以下代码：

public static <T> String marshall(T data) {
    try {
        JAXBContext jaxbContext = JAXBContext.newInstance(data.getClass());
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        StringWriter stringWriter=new StringWriter();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT,true);
        jaxbMarshaller.marshal(data, stringWriter);
        return stringWriter.toString();
    } catch (JAXBException e) {
        e.printStackTrace();
    }
    return null;
}