为什么hibernate用不同的别名返回相同的列？

Question

@Entity
public class Vehicle {
    
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private int number;
    private String name;
    
    @ManyToOne()
    private UserDetails user;
    
    public UserDetails getUserDetails() {
        return user;
    }
    public void setUserDetails(UserDetails user) {
        this.user = user;
    }
    public int getNumber() {
        return number;
    }
    public void setNumber(int number) {
        this.number = number;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    @Override
    public String toString() {
        return "Vehicle [number=" + number + ", name=" + name+"]";
    }
    
    

}
@Entity
public class UserDetails {

    @Id
    private int userId;

    private String userName;
    
    @OneToMany(cascade = CascadeType.ALL,mappedBy = "user")
    private List<Vehicle> vehicle=new ArrayList<Vehicle>();

    public List<Vehicle> getVehicle() {
        return vehicle;
    }

    public void setVehicle(List<Vehicle> vehicle) {
        this.vehicle = vehicle;
    }

    @Lob
    private String Description;

    public int getUserId() {
        return userId;
    }

    public void setUserId(int userId) {
        this.userId = userId;
    }

    public String getUserName() {
        return userName;
    }

    public void setUserName(String userName) {
        this.userName = userName;
    }
    public String getDescription() {
        return Description;
    }

    public void setDescription(String description) {
        Description = description;
    }

    @Override
    public String toString() {
        return "UserDetails [userId=" + userId + ", userName=" + userName + ", vehicle=" + vehicle + ", Description="
                + Description + "]";
    }
    

}
我得到了下面的结果。但是在这个结果中，高亮显示的行具有相同的列名，但是别名不同。为什么hibernate会得到相同的Cloumn？

冬眠：删除表，如果存在hibernate_sequence hibernate：删除表（如果存在）UserDetails Hibernate：如果存在，则删除表车辆Hibernate：创建表hibernate_sequence(next_val bigint)Engine=InnoDate：插入到hibernate_sequence值（1）Hibernate：创建表UserDetails（用户ID整数not null,Description longtext,用户名varchar(255),主键(userId))Engine=InnoDb Hibernate：创建表车辆（编号整数not null,name varchar(255),user_userId整数,主键（number））Engine=Innodb Hibernate：alter table车辆添加约束上午:15:22 org.hibernate.engine.transaction.jta.platform.internal.jtaplatformminitiator initiateService信息:hhh000490:使用JtaPlatform实现:[org.hibernate.engine.transaction.jta.platform.internal.nojtaPlatform]hibernate:从hibernate_sequence中选择next_val作为id_valfor update hibernate:update hibernate_sequence set next_val=？next_val=在哪里？Hibernate：在UserDetails（描述、用户名、用户ID）中插入值（？、？、？）Hibernate：在Vehicle（名称，user_userId，number)中插入值（？，？，？）Hibernate：选择userdetail0_.userid作为userid1_0_0_，userdetail0_.description作为descript2_0_0_，userdetail0_.username作为username3_0_0_from UserDetails userdetail0_where userdetail0_.userid=？Hibernate：选择vehicle0_.number as number1_1_0_，vehicle0_.name as name2_1_0_，vehicle0_.user_userid as user_use3_1_0_，userdetail1_.userid as userid1_0_1_，userdetail1_.description as descript2_0_1_，userdetail1_.username as username3_0_1_from Vehicle vehicle0_.user_detail1_左外部连接UserDetails userdetail1_上的userdetail1_Hibernate：选择vehicle0_.user_userid为user_use3_1_0_,vehicle0_.number为number1_1_0_,vehicle0_.number为number1_1_1_,vehicle0_.user_userid为user_use3_1_1_from Vehicle vehicle0_where vehicle0_.user_userid=？用户名==>UserDetails[Userid=0,Username=Vickram],Vehicle=[Vehictor[Number=1,name=CAR]],Description=高大白色]车辆====>UserDetails[Userid=0,Username=Vickram，Vehicle=[Vehictor[Number=1,name=CAR]],Description=高大白色]

Answer 1

这是因为版本6.0之前的Hibernate没有专门的SQL AST模型来删除重复。属性的每个列映射只是“传递”给SQL，即它为每个需要初始化的属性选择相应的映射列。