复杂XML文件的Java XML解析

Question

我真的希望你能在这件事上帮我....我需要从我的xml文件中获取特定的数据，但我卡在了一个点上，我不知道如何继续...

我想从网络获得：网络名称；From代码：mcc和mnc代码；From设置：名称、id、类型、参数名称、值；

这就是我的xml文件的结构：

<country country="Andorra" isoCode="AD">
    <networks>
        <network name="Mobiland" isMNO="true" ranking="10">
            <codes>
                <code mcc="213" mnc="03" />
            </codes>
            <settings>
                <setting alternativeName="Mobiland AD" ref="s1" name="IAP" id="2266" />
                <setting alternativeName="Mobiland MMS AD" ref="s2" name="MMS" id="2265" />
            </settings>
        </network>
    </networks>
    <settings>
        <setting id="s2" type="mmssetting">
            <parameter name="mms-gprs-access-point-name" value="MMS" />
            <parameter name="mms-gprs-name" value="MMS" />
            <parameter name="mms-gprs-proxy" value="192.168.021.050" />
            <parameter name="mms-gprs-proxy-port" value="9201" />
            <parameter name="mms-url" value="http://mms.ad/mmsc" />
        </setting>
        <setting id="s1" type="iapsetting">
            <parameter name="iap-gprs-access-point-name" value="internet" />
            <parameter name="iap-gprs-name" value="Internet" />
            <parameter name="iap-gprs-url" value="http://google.com" />
        </setting>
    </settings>
</country>

这就是我目前掌握的......我真的不能再继续下去了...在字符串content=CNode.GetLastChild（）.GetTextContent（）.Trim（）处有空指针异常；而我也不确定自己做这件事的方式是否正确.....

public void ReadXML（）引发ParserConfigurationException、SAXException、IOException{

    // Get the DOM Builder Factory
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

    // Get the DOM Builder
    DocumentBuilder builder = factory.newDocumentBuilder();

    // Load and Parse the XML document
    // document contains the complete XML as a Tree.
    Document document = builder.parse("D:\\test.xml");

    List<Apn> empList = new ArrayList<Apn>();

    // Iterating through the nodes and extracting the data.
    NodeList nodeList = document.getDocumentElement().getChildNodes();

    for (int i = 0; i < nodeList.getLength(); i++) {

        Node node = nodeList.item(i);
        if (node instanceof Element) {
            //Apn apn = new Apn();
            System.out.println(node.getAttributes().getNamedItem("country")
                    .getNodeValue());

            NodeList childNodes = node.getChildNodes();
            for (int j = 0; j < childNodes.getLength(); j++) {
                Node cNode = childNodes.item(j);


                if (cNode instanceof Element) {
                    String content = cNode.getLastChild().getTextContent()
                            .trim();

                    switch (cNode.getNodeName()) {
                    case "networks":
                        System.out.println(content);
                        break;
                    case "setting":
                        System.out.println(content);
                        break;
                    case "codes":
                        System.out.println(content);
                        // emp.location = content;
                        break;
                    }
                }
            }

        }

    }
}

谢谢！

Answer 1

我认为处理这样复杂的xml结构的最简单的方法是编写XSD模式并使用JAXB将xml转换为java对象