使用AngularJS和Firebase在用户之间传输项目

Question

好的，所以我正在使用AngularJS和Firebase，并试图在两个用户之间创建一个简单的交换。现在，我的数据结构被设置在“users/uid/”下面，然后是他们的电子邮件、他们加入的日期和gold。

在gold（users/uid/gold）下，我有“send”，它捕获了数量、时间和发送给谁（电子邮件）。这是下面的代码片段。它还更新了他们的总黄金。

现在我被困在更新他们送金子给的人。我捕获电子邮件地址，但范围内的所有内容都与当前登录的用户有关。我将如何更新新用户users/uid/gold/received的金额、时间和电子邮件，以及更新他们的总gold？

ledger.controller('TransferController', function (
$scope, $firebase, $routeParams, $location, $rootScope, FIREBASE_URL) {

    $scope.whichuser = $routeParams.uId;
    $scope.goldsends = goldsendList;

    var ref = new Firebase(FIREBASE_URL + '/users/' + $scope.whichuser + '/gold/' + '/sent/');
    var hopperRef = new Firebase(FIREBASE_URL + '/users/' + $scope.whichuser + '/gold/');
    var usersRef = ref.child("users");
    var goldsendList = $firebase(ref).$asArray();


    $scope.sendGold = function () {
        var sendgoldObj = $firebase(ref); //this var has to match the sendgoldObj.$push var down below, and that's it

        var myData = {
            amount: $scope.user.amount,
            email: $scope.user.email,
            date: Firebase.ServerValue.TIMESTAMP
        };

        sendgoldObj.$push(myData).then(function () {
            //   $location.path('/myledger/');  //page redirect
        }); //data sent to firebase.

        if ($scope.currentUser.gold.total - Math.abs($scope.user.amount) > 0) { //

            var hopperRefff = hopperRef.child("gold");
            hopperRef.update({
                "total": $scope.currentUser.gold.total - $scope.user.amount
            }); //update total gold

            var receive = new Firebase(FIREBASE_URL);
            ref.child('users').orderByChild('email').equalTo(emailAddress).once('value', function (snap) {
                console.log(snap.name() + (snap.val() === null ? ' DOES NOT' : ' does') + ' exist');
            }); //trying to find user to send gold to

        } //if user has enough gold statement
        else {
            return {
                scope: {
                    errormessage: 'You don\'t have enough money',
                }
            };
            console.log("not enough money!");
        } //else note enough gold statement

    } //sendgold
}); //TransferController

Answer 1

您可以通过电子邮件存储用户，其中@替换为_和.替换为-

所以在Firebase中有一个类似于这样的JSON结构

users: {
   "bob_hoskins-com": { 
      email: "[e-mail]",
      date: "09-09-1999",
      gold: {
          ...
      }
   }
}

然而，我不认为这是一个很好的方法来解决这个问题。

{
  "rules": {
    "$userId": {
      "requests": {
        ".read": "auth != null && $userId == auth.id",          
        ".write": "auth != null && $userId == auth.id"          
      },
      "responses": {
        ".read": "auth != null && $userId == auth.id",
        ".write": "auth != null && $userId == auth.id"          
      }
   }
}

var Firebase = require('firebase');

function s4() {
  return Math.floor((1 + Math.random()) * 0x10000)
             .toString(16)
             .substring(1);
}

function guid() {
  return s4() + s4() + s4() + s4();
}

var _ref = new Firebase('https://YOUR_FIREBASE.firebaseio.com/');

//Log me in
var guid = guid();
var FirebaseTokenGenerator = require("firebase-token-generator");
var tokenGenerator = new FirebaseTokenGenerator("YOUR_TOKEN");
var TOKEN = tokenGenerator.createToken({uid: guid, user: "node server"},{admin: true});

_ref.authWithCustomToken(TOKEN, function (error) {
  if(error) {
    console.log("Login Failed!", error);
  } else {
    console.log("Login Succeeded!", guid);
  }
});

_ref.on('child_added', function (user) {
    var requests = user.ref().child('requests');
    requests.on('child_added', function(req) {
        handleRequest(req);
    });
});

var handleRequest = function (request) {
   // Process the request
   // Write stuff back to Firebase

   // Delete the request
   request.ref().remove();
};