404错误Spring MVC

Question

我已经编写了一个Spring MVC应用程序，它显示了在XML视图中运行的测试用例和套件的报告。我已经编写了模型类，它很好，我已经编写了以下文件，但我想处理程序映射有一些问题

我的Controller.java类如下所示

package com.DrAssist.Fitnesse.controller;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;

import com.DrAssist.Fitnesse.model.Suite;



@Controller
@RequestMapping("/Suite/{name}")
public class XMLController {

    @RequestMapping(value="{name}", method = RequestMethod.GET, headers = "content-type=application/xml")
    public @ResponseBody Suite getSuiteInXML(@PathVariable String name) {

        Suite suite = new Suite("1",name,"3","Test1","4","5","7","9","550");

        return suite;

    }

}

<web-app id="WebApp_ID" version="2.4"
    xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Spring Web MVC Application</display-name>

    <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
    </context-param>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

</web-app>

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

    <context:component-scan base-package="com.DrAssist.Fitnesse.controller" />

    <mvc:annotation-driven />

    <!--  
    <bean class="org.springframework.web.servlet.view.BeanNameViewResolver" />

    <bean id="xmlViewer" 
        class="org.springframework.web.servlet.view.xml.MarshallingView">
        <constructor-arg>
            <bean class="org.springframework.oxm.jaxb.Jaxb2Marshaller">
                <property name="classesToBeBound">
                    <list>
                        <value>com.DrAssist.Fitnesse.model</value>
                    </list>
                </property>
            </bean>
        </constructor-arg>
    </bean>
    -->

</beans>

我得到一个404错误，控制台显示错误为

在名为“MVC-Dispatcher”的DispatcherServlet中，未找到URI为[/springmvc/suite/suite1]的HTTP请求映射

请注意，请求似乎没有通过/SpringMVC/suite/suite1]本身的SpringMVC部分。

提前致谢

Answer 1

您在@requestmapping中都放入了{name}路径变量。尝试将第一个保留为@requestmapping（“suite”）。