Camel rest-dsl发生异常时如何封送到JSON/XML

Question

我有一个带有绑定的REST-dsl骆驼路由:json_xml with.type()和outType（）。当没有异常发生时，它工作得很好。也就是说，json输入给出了json输出。Xml输入给出Xml输出。

onException(IllegalArgumentException.class)
        .log(LoggingLevel.ERROR, LOGGER, "error")
        .handled(true)
        .setHeader(Exchange.HTTP_RESPONSE_CODE, constant(400))
        .setHeader(Exchange.CONTENT_TYPE, exchangeProperty(Exchange.CONTENT_TYPE))
        .bean(errorResponseTranslator);
restConfiguration().component("restlet").port(port).skipBindingOnErrorCode(true)
        .bindingMode(RestBindingMode.json_xml);
    rest("/whatever/api/v1/request")
        .post().type(RequestDto.class).outType(ResponseDto.class)
            .route()
            .setProperty(Exchange.CONTENT_TYPE, header(Exchange.CONTENT_TYPE))
           ...process

@XmlRootElement(name = "errorResponse")
@XmlAccessorType(XmlAccessType.PROPERTY)
public class ErrorResponseDto {
  private String errorCode;
  private String message;

  @XmlElement(name = "message")
  public String getMessage() {
      return message;
  }

  public void setMessage(String message) {
      this.message = message;
  }

  @XmlElement(name = "errorCode")
  public String getErrorCode() {
      return errorCode;
  }

  public void setErrorCode(String errorCode) {
      this.errorCode = errorCode;
  }
}

Answer 1

您需要将内容类型explicit设置为XML

 .setHeader(Exchange.CONTENT_TYPE, exchangeProperty(Exchange.CONTENT_TYPE))

应该是

 .setHeader(Exchange.CONTENT_TYPE, constant("application/json"))