如何在同一个while循环中计算number大于和小于？

Question

// DiceRollProject.cpp : Defines the entry point for the console     application.
//

#include "stdafx.h"
#include <iostream>
#include <time.h>

using namespace std;

int diceRoll(int max);  // function definition
int getValidInteger();// function definition

int main() {

    srand(time(0)); // seed the random number generator

    int exitProgram = 0;
    int guess, rollValue;
    int maxRollValue = 6;
    cout << "Hello! Let's play a dice game. Let me do the first roll for you.\n" << endl;
    rollValue = diceRoll(maxRollValue);
    cout << "In this roll, you got: " << rollValue << "\n" << endl;

    do {
        rollValue = diceRoll(maxRollValue);


        cout << "What's your guess for the next roll? Enter an integer between 1 and " << maxRollValue << ": ";
        guess = getValidInteger();
        // TODO: Validate input

        if (guess > rollValue)
        {
            cout << "The guess was too high!";

        }

        if (guess < rollValue)
        {
            cout << "The guess was too low!";

        }

        if (guess == rollValue)
        {
            cout << "You guessed correctly, congrats!";

        }

        cout << "In this roll, you got: " << rollValue << "\n" << endl;
        // TODO: Evaluate result


        cout << "Enter 1 to exit or any other integer to continue rolling ";
        exitProgram = getValidInteger();
        cout << "\n";
        if (exitProgram == 1)
        {
            cout << "Sorry to see you go. Have a wonderful day!\n" << endl;
        }

    } while (exitProgram != 1);

    return 0;
}

// Roll the die
int diceRoll(int max) {
    int rollValue;

    rollValue = (rand() % max) + 1;

    return rollValue;
}


// Check if user entered an integer
int getValidInteger() {
    int userInput;

    cin >> userInput;

    while (userInput < 1)  {

        if (userInput < 1)
        {
            cout << "Please enter a number greater than or equal to 1\n";
        }

        if (userInput > 6)
        {
            cout << "Please enter a number less than or equal to 6\n";
        }

    }


    if (cin.fail()) {
        cin.clear();
        cin.ignore();
        cout << "Please enter an Integer only ";
        cin >> userInput;
        cout << "\n";
    }

    return userInput;
}

我有一个掷骰子猜谜游戏，我试图评估用户的输入，以确保他们不能输入小于1和大于6的数字，不幸的是，只有我的if语句，他们仍然可以输入这些数字，尽管显示一个字符串输入无效，我想做一个while循环，不断要求他们输入等于或大于1的有效数字和等于且小于 6，如果用户不断输入不正确的数字，while 循环将继续要求他们输入有效数字，直到他们输入一个，然后该数字将正常运行程序。

Answer 1

据我所知，你正在寻找这样的东西：

int main (){
int my_magic_number=(rand()%6)+1,usernumber=-1;
bool state;
while (usernumber!=my_magic_number){
     cin>>usernumber;
     state = (usernumber<1||usernumber>6);
     while (state) {
        cout<<"You entered a number outside the range [1,6] please try again\n";}
        cin>>usernumber;
        state = (usernumber<1||usernumber>6);
     }
    if (usernumber!=my_magic_number) {/* do whatever you want */}
} //while loop
} // main 

Answer 2

所以你的条件是，如果这个人猜得太高或太低，你就能留在while循环中。在while循环中，我将添加您想要重复的更新条件或语句。因此，在你的情况下，“你的猜测太高了”或“你的猜测太低了”，并再次要求他们的投入。我不是专业人士，但我会简单地构造两个while循环，一个用于过高，一个用于过低，就像你的if语句一样。实际上，您可以将前两个if语句改为while循环，并添加几行cout，让人们再次猜测并验证他们的输入。我希望这有所帮助。

Answer 3

首先，在while循环中有死代码。

while (userInput < 1)  {

    if (userInput < 1)
    {
        cout << "Please enter a number greater than or equal to 1\n";
    }

    if (userInput > 6)
    {
        cout << "Please enter a number less than or equal to 6\n";
    }

}

在循环体中，第一个if总是true，第二个if总是false。当用户写入无效输入时，应在循环中输入。当（userInput

在评估while的条件之后，您应该要求用户编写输入

do  {
    cout << "Please enter an Integer only ";
    cin >> userInput;
    if (userInput < 1)
    {
        cout << "Please enter a number greater than or equal to 1\n";
    }

    if (userInput > 6)
    {
        cout << "Please enter a number less than or equal to 6\n";
    }

}while(userInput < 1 || userInput > 6);