“尝试-捕获”选项在 Java 中不起作用

Question

我在试着写一个小数

package binary.with.decimal;

import java.util.Scanner;

public class RiaJava {

    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);

        int binaryp = 0;
        int n;
        int base = 2;
        int result = 0;
        int multiplier = 1;

        System.out.println("1.Binary to Decimal \n 2.Decimal to Binary");
        System.out.println("Enter Your Option Number:");
        n = scan.nextInt();

        switch (n) {
        case 1:
            System.out.println("Input Binary Number:");

            String binary = scan.nextLine();
            scan.close();
            try {
                binaryp = Integer.parseInt(binary);
            }

            catch (NumberFormatException e) {
                System.out.println("Wrong Input!!!");
            }

            while (binaryp > 0) {
                int residue = binaryp % base;
                binaryp = binaryp / base;
                result = result + residue * multiplier;
                multiplier = multiplier * 10;
            }
            System.out.println("Decimal....." + result);

            break;
        case 2:
            System.out.println("Input Decimal Number:");
            int decimal = scan.nextInt();
            scan.close();

            while (decimal > 0) {
                int residue = decimal % base;
                decimal = decimal / base;
                result = result + residue * multiplier;
                multiplier = multiplier * 10;
            }
            System.out.println("Binary....." + result);
            break;
        default:
            System.out.println("you have selected wrong option number");
            break;
        }
    }
}

Answer 1

＜代码＞扫描。nextLine（）应该是scan.next（）

nextLine（） 不等待用户输入，而是读取剩余的缓冲区，直到下一行末尾。