基于Neo4j的大型图节点度查询（百万节点和链接）

Question

start n = node(*) 
match (n)--(c)
return n, count(*) as connections
order by connections dsec

g.V.bothE

有人在neo4j上用gremlin或Cypher查询这么大的图形吗？

Answer 1

对于最大的程度，您也应该限制结果，所以cypher将只保留前10个结果。

START n = node(*) 
MATCH (n)--(c)
RETURN n, count(*) as connections
ORDER BY connections DESC
LIMIT 10

或者你可以做：

START n = node(*)
RETURN n, length((n)--(c)) as connections
ORDER BY connections DESC
LIMIT 10

否则我同意斯特凡的观点。