用于Spring缓存管理器的Junit

Question

我在我的应用程序中使用了spring缓存层，我在编写使用Mockito测试spring缓存层的单元测试时遇到了一个问题。

    public CustomerServiceImpl implements CustomerService {
    @Autowired
    private CacheManager cacheManager;

    @Autowired
    private CustomerRepository customerRepository;//Repository is simple JPA repository interface which contains findByCustomerName()

    @Override
    @CachePut(value = "#customer", key = "#customer.customerName")
    public Customer insertOrUpdate(Customer customer) {
        return customerRepository.save(customer);
    }

    @Cacheable(value="customersCache", key = "#customerName")
    public Customer findByCustomerName(String customerName) {
        Customer customer = customerRepository.findByCustomerName(customerName);
        return customer;
    }
}

服务层的JUnit测试代码：

@RunWith(PowerMockRunner.class)
@PrepareForTest(CustomerServiceImplTest.class)
public class CustomerServiceImplTest {

    @Spy
    CacheManager cacheManager = new ConcurrentMapCacheManager("customersCache");

    @Mock
    CustomerRepository CustomerRepository;

    @InjectMocks
    CustomerServiceImpl customerServiceImpl = new CustomerServiceImpl();

    @Before
    public void setup() {
        MockitoAnnotations.initMocks(this);
    }

    @Test
    public void testCacheForFindByCustomerName() {
        Customer customer1 = new Customer();
        customer1.setId("1");
        customer1.setName("John");
        Customer customer2 = new Customer();
        customer2.setId("2");
        customer2.setName("Sara");

        //this should save to cache   
        Mockito.when(CustomerRepository.save(customer1))
        .thenReturn(customer1);
        customerServiceImpl.insertOrUpdate(customer1);

        //Now it should retreive from cache, but not able to
      Mockito.when(CustomerRepository.findByCustomerName(Mockito.any(String.class)))
                .thenReturn(customer1, customer2);

        Customer result = customerServiceImpl.findByCustomerName("John");
        assertThat(result, is(customer1));

        result = customerServiceImpl.findByCustomerName("John");
        assertThat(result, is(customer1));
    }
}

例外情况：

我得到了一个“java.lang.AssertionError:”，因为缓存层没有工作，并且调用被传递到repository对象（两次），该对象返回了上面的'Customer2'模拟对象，即通过传递服务层，对同一个键调用了两次repository方法。

Answer 1

Spring缓存管理器依赖于Spring管理应用程序。您无法用PowerMockRunner实现这一点，您需要使用SpringJunit4Runner。您仍然可以以编程方式使用PowerMock或Mockito，但不能作为运行器使用。

通常，您将把单元测试转换为Spring样式的集成测试，如下所示：

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration
public class SpringTest {

    @Configuration
    @EnableCaching
    static class SpringConfig{
        @Bean
        public CustomerService customerService(){
            return new CustomerServiceImpl(customerRepository());
        }
        @Bean
        public CustomerRepository customerRepository(){
            return Mockito.mock(CustomerRepository.class);
        }
    }

    @Autowired
    CustomerService customerService; // this will contain a proper managed cache

    @Autowired
    CustomerRepository customerRepository; // this is a mockito mock you can fine-tune
}