从命令行执行文件夹名中有空格的Jar文件

Question

Input File Path as argument to program

File Path : E:\TestCode\Test file space\abc.xml

Code : This code will accept the above file path as argument.

package com.org;

import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;

public class FileSepratorTest {

    public static void main(String[] args) {
        String filePath = args[0];    // It will take file path as E:\TestCode\Test file space\abc.xml
        try {
            System.out.println("File Path :"+filePath);  // printing file path
            FileInputStream file = new FileInputStream(new File(filePath)); 
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

}


Exception occurs when execute this code with space separated folder name

File Path :E:\TestCode\Test

java.io.FileNotFoundException：E:\testcode\test（系统找不到指定的文件）
在java.io.FileInputStream.Open（本机方法）在java.io.FileInputStream.（未知源）在com.org.FileSpratortTest.Main（FileSpratortest.java:16)

它不显示整个文件路径，我知道我需要把它作为参数，但我想要执行jar文件，jar文件路径指定如下

E:\TestCode\executable_jar>java -cp E:\TestCode\executable_jar\abc_lib -jar redmas-    migration.jar E:\TestCode\Migration Letest File\abc.xml** **in my application.  

Answer 1

用“-双引号环绕文件路径

e:\testcode\executable_jar>java-cp e:\testcode\executable_jar\abc_lib-jar redmas-migration.jar“e:\testcode\migration Letest file\abc.xml”