如何将字符串的个数乘以一个数

Question

String laoder = "#";
int rounds = 1000; // Could be 10000, 250000, 60000, ... 
// This is 1% 
int number = 1000 / 100;
for(int i=0; i < 1000; i++){
    // This is X % 
    if(i == number) {
        // I want to print the # every 10 % and the normale percentage every 1% 
        // For example 
        // [#         ] 1%
        // [#         ] 2%
        // ....
        // [##        ] 10%
        // [##########] Done
        System.out.printf("[# %s                    ] \r \s%", loader * (number / number), number);
        // This work, but how can I combine both
        System.out.print(repeat(laoder , number / 10) + " \r");
        number += number;
    }

    Thread.Sleep(500)
}
public static String repeat(int count, String with) {
    return new String(new char[count]).replace("\0", with);
}

Answer 1

这确实是一个有趣的问题来解决。下面是一种方法。所有计算都是使用整数（没有浮点）完成的。

只需注意总数必须大于0。

玩得开心！

int total = 100; // must be greater than 0
char[] progressBar = new char[10];
Arrays.fill(progressBar, ' ');
for (int progress = 0; progress <= total; progress++) {
    int percentage = progress * 100 / total;
    Arrays.fill(progressBar, 0, percentage / 10, '#');
    System.out.println("[" + String.valueOf(progressBar) + "] " + percentage + "%");
}

[          ] 0%
[#         ] 10%
[##        ] 20%
[###       ] 30%
[####      ] 40%
[#####     ] 50%
[######    ] 60%
[#######   ] 70%
[########  ] 80%
[######### ] 90%
[##########] 100%