“PersistenceException:HibernateeException:找到了多个具有给定标识符的行”-运行select查询时

Question

• Eclipse版本：2021-06 (4.20.0)构建id：20210612-2011
• Jdk 15.0.2
• 雄猫8.5.75
• Maven 3.8.4
• 冬眠5.4.22。最终

执行此查询会引发异常：

            userObject = (User) session.createQuery("FROM User U WHERE U.username = :userName")
                .setParameter("userName", userName).uniqueResult();

@Entity
@Table(name = "users")
public class User implements Serializable {
    
    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(name = "structure_id")
    private Structure structure;

@Entity
@Table(name = "structure")
public class Structure implements Serializable {

    @OneToOne(mappedBy = "structure")
    private User user;

一个User只能有一个结构，一个结构可以有很多个Users

CREATE TABLE `structure` (
  `structure_id` int NOT NULL,
  `nom_structure` varchar(255) DEFAULT NULL,
  PRIMARY KEY (`structure_id`),
  UNIQUE KEY `UK_irbn1likcfwrr1wckpjifcsv` (`nom_structure`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb3

CREATE TABLE `users` (
  `user_id` int NOT NULL,
  `email` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_0900_ai_ci DEFAULT NULL,
  `etat` int DEFAULT NULL,
  `phone` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_0900_ai_ci DEFAULT NULL,
  `first_name` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_0900_ai_ci DEFAULT NULL,
  `last_name` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_0900_ai_ci DEFAULT NULL,
  `password` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_0900_ai_ci DEFAULT NULL,
  `username` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_0900_ai_ci DEFAULT NULL,
  `dateExpiration` date DEFAULT NULL,
  `currentAccessDate` datetime(6) DEFAULT NULL,
  `lastAccessDate` datetime(6) DEFAULT NULL,
  `structure_id` int DEFAULT NULL,
  PRIMARY KEY (`user_id`),
  KEY `FK7qgxvgafv4ohh16kh0fgfm4b0` (`structure_id`),
  CONSTRAINT `FK7qgxvgafv4ohh16kh0fgfm4b0` FOREIGN KEY (`structure_id`) REFERENCES `structure` (`structure_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb3

javax.persistence.PersistenceException: org.hibernate.HibernateException: More than one row with the given identifier was found: 964, for class: com.myProject.helpdesk.models.Structure
    at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:154)
    at org.hibernate.query.internal.AbstractProducedQuery.list(AbstractProducedQuery.java:1542)
    at org.hibernate.query.internal.AbstractProducedQuery.uniqueResult(AbstractProducedQuery.java:1575)
    at com.myProject.helpdesk.dao.UserDao.validate(UserDao.java:50)
    at com.myProject.helpdesk.controllers.Login.authenticate(Login.java:74)
    at com.myProject.helpdesk.controllers.Login.doPost(Login.java:58)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:652)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:733)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:231)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
    at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
    at com.myProject.helpdesk.util.CharacterEncodingFilter.doFilter(CharacterEncodingFilter.java:33)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:199)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:97)
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:544)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:143)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:81)
    at org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:690)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:78)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:343)
    at org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:616)
    at org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:65)
    at org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:831)
    at org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1634)
    at org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
    at java.base/java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1130)
    at java.base/java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:630)
    at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
    at java.base/java.lang.Thread.run(Thread.java:832)

我认为Structure类的注释映射是错误的，应该是：

@OneToMany(mappedBy = "structure")
private List<User> user;

而不是这个：

@OneToOne(mappedBy = "structure")
private User user;

我只需要在运行这个简单的select查询时返回一个用户对象

        userObject = (User) session.createQuery("FROM User U WHERE U.username = :userName")
            .setParameter("userName", userName).uniqueResult();

任何帮助赞赏。

Answer 1

鉴于此

一个用户只能有一个结构，一个结构可以有多个用户

您确实应该考虑更改映射到@ OneToMany。

顺便说一下，尽量避免像这样的铸件：

userObject = (User) session.createQuery("FROM User U WHERE U.username = :userName")
            .setParameter("userName", userName).uniqueResult();

相反，通过将预期的实体类作为第二个参数传递给Session:：createQuery方法，将查询转换为TypedQuery，如下所示：

userObject = session.createQuery("FROM User U WHERE U.username = :userName", User.class)
            .setParameter("userName", userName).uniqueResult();