如何在java中修改HttpServletRequest正文？

Question

我想在请求正文到达Http Servlet并获得processed.The请求正文的JSON有效负载如下所示，我想摆脱“PayamtChqmanViewObject”（详细信息）部分。

{
      "ChqAccCode": "1",
      "ChqAmt": 1,
      "ChqBankCompCode": "TEST",
      "ChqBchName": "TEST",
      "ChqBchPost": "Y",
      "ChqPostDate":"2020-08-14",
      "ChqCompCode": "TEST",
      "ChqDate": "2020-04-21",
      "ChqDeptCode": "0",
      "ChqDesc": "TEST",
      "ChqDraftCode": "M",
      "ChqJobCode": null,
      "ChqJointVenName": null,
      "ChqNum": 123,
      "ChqPayeeAddr1": "Rome",
      "ChqPayeeAddr2": "1",
      "ChqPayeeAddr3": "Rome",
      "ChqPayeeCountry": "Italy",
      "ChqPayeeName1": "A1",
      "ChqPayeeName2": null,
      "ChqPayeePostalCode": "85695",
      "ChqPayeeRegCode": "IT",
      "ChqRecCode": "O",
      "ChqSeqNum": "1",
      "ChqVenCode": "ZZ",
      "ChqVouCode": null,
      "PayamtChqmanViewObj":[
        {
          "PaCompCode": "ZZ",
          "PaChqCompCode": "ZZ",
          "PaVenCode": "ACME",
          "PaChqNum": 123,
          "PaPayCurrAmt": 1,
          "PaAmt": 1,
          "PaVouInvCode": "INV001",
          "PaDiscAmt": 0,
          "PaChqSeqNum": "1"
        }
   ]
}

我可以使用以下方法获得请求正文，但我不知道如何删除JSON的详细部分并将处理后的请求正文传递给HTTP Servlet。

 public static String getBody(HttpServletRequest request) throws IOException {

        String body = null;
        StringBuilder stringBuilder = new StringBuilder();
        BufferedReader bufferedReader = null;

        try {
            InputStream inputStream = request.getInputStream();
            if (inputStream != null) {
                bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
                char[] charBuffer = new char[128];
                int bytesRead = -1;
                while ((bytesRead = bufferedReader.read(charBuffer)) > 0) {
                    stringBuilder.append(charBuffer, 0, bytesRead);
                }
            } else {
                stringBuilder.append("");
            }
        } catch (IOException ex) {
            throw ex;
        } finally {
            if (bufferedReader != null) {
                try {
                    bufferedReader.close();
                } catch (IOException ex) {
                    throw ex;
                }
            }
        }

        body = stringBuilder.toString();
        System.out.println("BODY IS:" + body);
        return body;
    }

非常感谢您的帮助！

Answer 1

你不能改变请求，但你可以包装它。更多细节请看下面的问题:我们为什么要包装HttpServletRequest？api提供了一个HttpServletRequestWrapper，但是我们从包装请求中获得了什么呢？

您需要在servlet前面放置一个servlet过滤器才能使包装工作。

至于如何从内容中删除该部分，您可以使用string类提供的普通旧字符串操作，或者使用类似StringUtils的东西，或者您可以使用自己选择的库解析JSON，删除该属性，然后将其写回字符串。