用Java编写宾果游戏遇到麻烦

Question

我是Java新手，我得到了一个项目，我需要创建一个宾果游戏，这意味着要在cmd/终端中玩。我有麻烦替换2D数组中的数字（如果玩家输入匹配2张卡中的任何一张，它被替换为“xx”，然后继续与标记为“xx”的数字的游戏），并检查用户是否在一行中获得了所有的数字，然后沿着“宾果，玩家”名称“赢了！”的线显示一些东西（将有2个玩家卡只）。我也想不出如何阻止用户输入已经划掉/重复的数字。

import java.util.Scanner;
public class demno {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int call, r = 0, c = 0;   /* For the player to input bingo numbers. 
                            To declare row and column globally for later use. */

        // Initiate card 1 numbers
        int[][] card1 = { {24, 2,  8, 1,  25},
                          {12, 16, 7, 17, 15},
                          {5, 6, 20, 19, 13 },
                          {14, 23, 22, 4, 3 },
                          {10, 18, 11, 21, 9} };
        // Initiate card 2 numbers
        int[][] card2 = { {24, 21, 17, 15, 6},
                          {10, 3, 8, 18, 20  },
                          {14, 7, 16, 12, 5  },
                          {25, 23, 13, 19, 11},
                          {22, 4, 9, 1, 2    } };


        // Player 1's card
        System.out.println("Player 1's card:");
        for (r=0; r<card1.length; r++) {
            for(c=0;c<card1.length; c++){
                if (10 > card1[r][c] ){
                    System.out.print(" "+ card1[r][c] +" ");
                }else {
                    System.out.print(card1[r][c] + " ");
                }
            }
            System.out.println("");
        }
        // End Player 1's card
        
        System.out.print('\n');
        // Player 2's card
        System.out.println("Player 2's card:");
        for (r=0; r<card2.length; r++) {
            for(c=0;c<card2.length; c++){
                if (10 > card2[r][c]) {
                    System.out.print(" " + card2[r][c] + " ");
                }else {
                    System.out.print(card2[r][c] + " ");
                }
            }
            System.out.println("");
        }
        // End Player 2's card

        // User input for bingo number
        System.out.println();
        System.out.print("Game Host call (0 to exit): ");
            call = sc.nextInt();
            sc.close();
        // Checks user input for errors or if player want's to exit.
        if (call >25) {
            System.out.println("The number must be between 1 to 25, please call again! ");
            System.out.print("Game Host call (0 to exit): ");
            call = sc.nextInt();
            sc.close();
        }else if (call == 0) {
            System.exit(0);
        }

        }

    }

Answer 1

可以用array[0]=“xx”替换数组中的值。因此，在您的示例中，它将是card2[r][c]=“xx”。

为了确保每个数字都使用一次，一个简单的解决方案是ArrayList。所以你可以用它

List<Integer> usedNumbers = new ArrayList<Integer>();

//  when number was used
usedNumbers.add(call);

//check if already used
boolean alreadyUsed = usedNumbers.contains(call);

Tipp：

  for (r=0; r<card2.length; r++) {

        for(c=0;c<card2.length; c++){

  for (r=0; r<card2.length; r++) {

        for(c=0;c<card2[r].length; c++){

如果点变量之一==5，打印赢家并停止应用程序