尝试打印方法时出现字符串格式错误

Question

无法打印出格式错误弹出的结果。

1. 尝试在没有getWaitingTime（）和%-20d（最后一个）的情况下执行，它可以工作。
2. 尝试执行1，并用getWaitingTime（）替换seqNo，它可以工作。

不确定是什么错误。

import java.util.*;
public class Customer {

  private int seqNo;
  private Calendar arrTime;
  private Calendar serveTime;
  private int counter;

  public Customer(int seqNo) {
    this.seqNo = seqNo;
    this.arrTime = new GregorianCalendar();
  }

  public int getSeqNo() {
    return seqNo;
  }

  public int getCounter() {
    return counter;
  }

  public void setServeTime(Calendar serveTime) {
    this.serveTime = serveTime;
  }

  public void setCounter(int counter) {
    this.counter = counter;
  }

  public static String getTime(Calendar time) {
    return String.format("%02d:%02d:%02d", time.get(Calendar.HOUR_OF_DAY),
            time.get(Calendar.MINUTE), time.get(Calendar.SECOND));
  }

  public int getWaitingTime() {
    return (int) ((serveTime.getTimeInMillis() - arrTime.getTimeInMillis()) / 1000);
  }

  public String toString() {
    return String.format("%-12d %-23s %-27s %-20s %-12d",
            seqNo, getTime(arrTime), getTime(serveTime), "Counter " + counter + getWaitingTime());
  }

}

它调用toString方法的部分。它从servicelist被称为。

private ArrayList<Customer> serviceList = new ArrayList<Customer>();

private void jbtReportActionPerformed(java.awt.event.ActionEvent evt) {                                          
        JTextArea jtaReport = new JTextArea(50, 200);
        String str = String.format("%70s\n", "Service Analysis Report");
        str += String.format("%-5s %-10s %-20s %-20s %-15s %-15s\n",
                "No", "Seq. No", "Arr. Time (ms)", "Serve Time(ms)", "Counter", "Waiting Time(s)");
        
        for(int i=0; i<serviceList.size(); i++){
            int no = i+1;
            str += String.format("%-9s %80s\n", no, serviceList.get(i).toString());
        }
        
        Font reportFont = new Font("Arial", Font.BOLD, 14);
        jtaReport.setText(str);
        jtaReport.setEditable(false);
        jtaReport.setFont(reportFont);
        JFrame reportFrame = new JFrame();
        reportFrame.add(jtaReport);
        reportFrame.setSize(600, 800);
        reportFrame.setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
        reportFrame.setVisible(true);
    }

至于错误是：

JAVAutil。MissingFormatArgumentException:邮局的格式说明符'-12d'。顾客toString（Customer.java:49）

这是返回字符串格式（“%-12d，…”）在顾客那里。因为它可以在没有最后一个%-12d的情况下运行，所以我认为问题在于最后一个%-12d。

Answer 1

将Tostring（）处的“”替换为“，”

public String toString() {
    return String.format("%-12d %-23s %-27s %-20s %-12d",
            seqNo, getTime(arrTime), getTime(serveTime), "Counter " + counter, getWaitingTime());
  }